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enot [183]
3 years ago
7

Yall pls help me out

Engineering
1 answer:
atroni [7]3 years ago
8 0

Answer:

M·L/T²

Explanation:

The given equation for <em>T</em> is presented as follows;

T = \dfrac{M \cdot V^2 \cdot A}{L^3}

Where;

m = Mass with dimension M

V = Velocity, having the dimensions L/T

A = Area, having the dimensions L²

l = Length, having the dimensions, L

Therefore;

The \ dimensions \ of \ T = \dfrac{M \times (L/T)^2 \cdot L^2}{L^3} =  \dfrac{M \times L^4/T^2 }{L^3} = M \cdot L/T^2

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A piston-cylinder device contains 0.58 kg of steam at 300°C and 0.5 MPa. Steam is cooled at constant pressure until one-half of
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b) ΔV = - 0.194 m³

c) The T-V diagram is sketched in the image attached.

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