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Yanka [14]
3 years ago
11

Diatomic n2 can react with diatomic h2 to form ammonia (nh3). the balanced chemical equation is: n2 + 3 h2 ? 2 nh3 if 6 moles of

h2 totally reacted with more than enough n2, how many moles of ammonia would be expected to form?
Chemistry
1 answer:
Helga [31]3 years ago
6 0
The balanced chemical reaction is as shown below,

                 N₂ + 3H₂  --> 2NH₃

The equation shows that every 3 moles of hydrogen, H2, there would be 2 moles of ammonia, NH3, that is going to be formed. Using this concept, we solve for the unknown in this item. 

Since we are restricted only of the number of hydrogen, it becomes our limiting reactant. 

          (6 moles H2) x (2 moles NH3/3 moles H2) = <em>4 moles NH3</em>

Therefore, given enough amount of N2, the amount of NH3 that can be formed out of the 6 moles of H2 is equal to 4 moles. 
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What is the salt formers group number is?
NeTakaya

The halogens are five non-metallic elements found in group 17 of the periodic table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts". All halogens have 7 electrons in their outer shells, giving them an oxidation number of -1.

3 0
2 years ago
An object's velocity can be described by its acceleration and direction.<br><br> True<br> False
coldgirl [10]

Answer:

False

Explanation:

An object's velocity can be described by it's direction. Because velocity is a vector. Besides velocity and acceleration are different units they can't be described by each other.

7 0
2 years ago
Predict the products of La(s) + O2(aq) -&gt;
mina [271]

Answer:

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

Explanation:

<em>Hello </em><em>there!</em>

When you are given such a problem for completing the chemical equations, what you have to understand is that metals are found in groups I, II and III. While Oxygen is a group VI element.

From the above question I have considered that my La(s), solid is either Sodium (Na) - group I, Magnesium - group II and Aluminum - group III.

In a reaction, there is exchange of electrons given by their oxidation numbers (I, II and III - for our metals above)

The chemical equations are thus;

i. Na (s) + O2 (g) => NaO (s)

ii. Mg (s) + O2 (g) => Mg2O (s)

iii. Al (s) + O2 (g) => Al2O3 (s)

Relate this to the problem and it will be;

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

<em>I hope this </em><em>helps </em><em>you</em><em> </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Enjoy </em><em>your</em><em> </em><em>studies</em>

3 0
2 years ago
A thermometer reads an outside air temperature of 35°c. What is the temperature in degrees Fahrenheit
Hoochie [10]

35°c is equal to 95°f

To do this multiply 35 and 1.8

35 x 1.8=63

Now add 32

Resulting in the answer 95

(The equation for to solve for c and f is c1.8+32=f

3 0
2 years ago
What is the molarity of a 500.0 ml solution containing 0.75 moles of solute?
wariber [46]
M=mol/L
M=.75/.5
M=1.5
4 0
3 years ago
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