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3 years ago

a body thrown vertically upwards from grounf with inital vel 40m/s then time taken by it to reach max hieght is?

Physics

1 answer:

777dan777 [17]3 years ago

4 0

Answer:

t = 4.08 s

Explanation:

if the body is thrown upward, it has negative gravity. Knowing through the International System that the earth's gravity is 9.8 m/s²

Data:

Vo = 40 m/s
g = -9.8 m/s²
t = ?

Use formula:

$\boxed{\bold{t=\frac{-(V_{0})}{g}}}$

Replace and solve:

$\boxed{\bold{t=\frac{-(40\frac{m}{s})}{-9.8\frac{m}{s^{2}}}}}$

$\boxed{\boxed{\bold{t=4.08\ s}}}$

Time taken by it to reach max height is <u>4.08 seconds.</u>

Greetings.

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Answer:

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Explanation:

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$R_{N}$ = 5.6 × 9.81 = 54.9 N

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At point 1

$K_{1} = \frac{1}{2} m v^{2} _{1}$

$K_{1} = 0$

$U_{1} = \frac{1}{2} k x^{2}$

$U_{1} = \frac{1}{2} (1040) 0.035^{2}$

$U_{1} =$ 0.637 J

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$K_{2} = \frac{1}{2} (5.6) v^{2} _{2}$

$K_{2} = 2.8 v_{2} ^{2}$

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$U_{2} = \frac{1}{2} (1040) 0.02^{2}$

$U_{2} = 0.208$ J

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Answer

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