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Nesterboy [21]
3 years ago
12

a body thrown vertically upwards from grounf with inital vel 40m/s then time taken by it to reach max hieght is?

Physics
1 answer:
777dan777 [17]3 years ago
4 0

Answer:

t = 4.08 s

Explanation:

if the body is thrown upward, it has negative gravity. Knowing through the International System that the earth's gravity is 9.8 m/s²

Data:

  • Vo = 40 m/s
  • g = -9.8 m/s²
  • t = ?

Use formula:

  • \boxed{\bold{t=\frac{-(V_{0})}{g}}}

Replace and solve:

  • \boxed{\bold{t=\frac{-(40\frac{m}{s})}{-9.8\frac{m}{s^{2}}}}}
  • \boxed{\boxed{\bold{t=4.08\ s}}}

Time taken by it to reach max height is <u>4.08 seconds.</u>

Greetings.

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5 0
3 years ago
Two conducting parallel plates 5.0 × 10−3 meter apart are charged with a 12-volt potential
photoshop1234 [79]

Answer: 2.4×10^-3 v/m

Explanation: distance between plates of capacitor (d) =5.0×10^-3m

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The formulae that relates potential difference, eoectiic field strength and distance between plates is given as

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7 0
3 years ago
A 50 kg pitcher throws a baseball with a mass of 0.15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is
Andreas93 [3]

The velocity of the pitcher is <u>0.105 m/s</u> in a direction opposite to the velocity of the ball.

When no external force acts on a system, the total momentum of the system is conserved. The total initial momentum of the system is equal to the total final momentum of the system.

The pitcher and the ball are initially at rest, therefore, the total initial momentum of the system is zero.

Since no external forces act on the system comprising of pitcher and the ball, the total final momentum of the system is also equal to zero.

If the mass of the pitcher is mp and its speed is vp, the mass of the ball is mb and the ball's speed is vb, then the final momentum of the system of pitcher and the ball is given by,

p=m_pv_p+m_bv_b=0

Therefore,

v_p=-\frac{m_b}{m_p} v_p

Substituet 0.15 kg for mb, 50 kg for mp and 35 m/s for vb.

v_p=-\frac{m_b}{m_p} v_p=-\frac{0.15 kg}{50 kg} (35m/s)=-0.105 m/s

The pitcher has a velocity <u> 0.105 m/s</u> opposite to the direction of the velocity of the ball.

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