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Gre4nikov [31]
3 years ago
6

Which equation could be rearranged to calculate the frequency of a wave?

Physics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

wavelength = speed/frequency

Explanation:

Required

Determine which of the options can be used to calculate frequency

The relationship between wavelength, speed and frequency is as follows;

Frequency = \frac{Wave\ Speed}{Wave\ Length} ---- Equation 1

When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does

Checking option (3)

Wave\ Length = \frac{Speed}{Frequency}

Multiply both sides by Frequency

Wave\ Length * Frequency = \frac{Speed}{Frequency} * Frequency

Wave\ Length * Frequency = Speed

Divide both sides by Wave Length

\frac{Wave\ Length * Frequency}{Wave\ Length} = \frac{Speed}{Wave\ Length }

Frequency = \frac{Speed}{Wave\ Length } --- Equation 2

<em>Comparing equation 1 and 2; both equations are the same.</em>

<em>Hence, option (3) answers the question</em>

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An electron has a kinetic energy of 3.00 ev. find its wavelength. (b) what if? a photon has energy 3.00 ev. find its wavelength.
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(a) The electron kinetic energy is
K=3.00 eV
which can be converted into Joule by keeping in mind that
1 eV=1.6 \cdot 10^{-19}eV
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The kinetic energy of the electron is related to its momentum p by:
K= \frac{p^2}{2m}
where m is the electron mass. Re-arranging the equation, we find
p= \sqrt{ 2Km}= \sqrt{ 2  ( 4.8 \cdot 10^{-19} J)(9.1 \cdot 10^{-31} kg) } =9.35 \cdot 10^{-25} kgm/s

And now we can use De Broglie's relationship to find its wavelength:
\lambda= \frac{h}{p}= \frac{6.6 \cdot 10^{-34} Js}{9.35 \cdot 10^{-25} kg m/s} =7.06 \cdot 10^{-10}m
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(b) By using the same procedure of part (a), we can convert the photon energy into Joules:
E=3.00 eV \cdot 1.6 \cdot 10^{-19} eV/J =4.8 \cdot 10^{-19}J

The energy of a photon is related to its frequency f by:
E=hf
where h is the Planck constant. Re-arranging the equation, we find
f= \frac{E}{h}= \frac{4.8 \cdot 10^{-19} J}{6.6 \cdot 10^{-34}Js} =7.27 \cdot 10^{14}Hz

And now we can use the relationship between frequency f, speed of light c and wavelength \lambda of a photon, to find its wavelength:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.27 \cdot 10^{14} Hz} =4.13 \cdot 10^{-7} m
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I need help please so fast
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Answer:

DUumb

Explanation:

Duumb

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How will a wave change as it moves from a layer of higher velocity into a lower layer of lower velocity?
denis-greek [22]

Explanation:

Wave is defined as a disturbance or oscillation that travels through space-time, accompanied by a transfer of energy. Wave motion transfers energy from one point to another, often with no permanent displacement of the particles of the medium.

The velocity of wave is equal to the product of its wavelength and frequency (number of vibrations per second). Longitudinal waves like sound waves travel through a medium.

Therefore, a wave move from a layer of high velocity to that of a lower velocity the wavelength changes (that is, decreases) as it moves.

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