All categories

4 years ago

Which equation could be rearranged to calculate the frequency of a wave?

Physics

1 answer:

777dan777 [17]4 years ago

7 0

Answer:

wavelength = speed/frequency

Explanation:

Required

Determine which of the options can be used to calculate frequency

The relationship between wavelength, speed and frequency is as follows;

$Frequency = \frac{Wave\ Speed}{Wave\ Length}$ ---- Equation 1

When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does

Checking option (3)

$Wave\ Length = \frac{Speed}{Frequency}$

Multiply both sides by Frequency

$Wave\ Length * Frequency = \frac{Speed}{Frequency} * Frequency$

$Wave\ Length * Frequency = Speed$

Divide both sides by Wave Length

$\frac{Wave\ Length * Frequency}{Wave\ Length} = \frac{Speed}{Wave\ Length }$

$Frequency = \frac{Speed}{Wave\ Length }$ --- Equation 2

<em>Comparing equation 1 and 2; both equations are the same.</em>

<em>Hence, option (3) answers the question</em>

You might be interested in

A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nC/m) is bent to form a semicircle. What is the magnitude

Yuki888 [10]

Answer:

The magnitude of the electric field at the center of the circle is 85 N/C

The correct option is b. 85 N/C

Explanation:

Please see the attachments below

8 0

3 years ago

Differences between fundamental and derived quantities

monitta

Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

6 0

2 years ago

A shovel pushes on dirt and the dirt pushes back on the shovel. The dirt pushing back is

Leno4ka [110]

The dirt pushing back is the 'resistance' force. It RESISTS your attempts to shovel it.

6 0

3 years ago

A planet has two small satellites in circular orbits around the planet. the first satellite has a period 18.0 hours and an orbit

puteri [66]

The two satellites orbit around the same planet, so we can use Kepler's third law, which states that the ratio between the cube of the radius of the orbit and the orbital period is constant for the two satellites:
$\frac{r_1^3}{T_1^2}= \frac{r_2^3}{T_2^2}$
where
$r_1$ is the orbital radius of the first satellite
$r_2$ is the orbital radius of the second satellite
$T_1$ is the orbital period of the first satellite
$T_2$ is the orbital period of the second satellite

If we use the data of the problem and we re-arrange the equation, we can calculate the orbital period of the second satellite:
$T_2 = \sqrt{T_1^2 ( \frac{r_2}{r_1} )^3} = \sqrt{(18.0 h)^2 ( \frac{3\cdot 10^7 m}{2 \cdot 10^7 m} )^3} = 33.1 h$

8 0

3 years ago

150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc

Free_Kalibri [48]

<h2>Answer:</h2>

Acceleration= -1.11 m/sec²

<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

3 0

4 years ago