Answer:
Half of the moon or 50%
Explanation:
The first quarter phase of the moon is when the Sun illuminates the half part of the moon while the other half rest in darkness.
In the first quarter phase of the moon, the illumination on the moon surface keeps on rising.
When the new moon appear, there is no illumination while the illumination is 100 % on Full moon.
For the phases of crescent moon, it ranges from 0 - 50% and then for gibbous phase, the range of the illumination is from 50-100%from new
Answer:
The acceleration caused by a net force of 2 N on a 2 kg mass is 1 m/s²
Explanation:
The given parameters on an applied force is as follows;
The acceleration given to a 1 kg mass by a 1-N net force = 1 m/s²
According to Newton's second law of motion, the acceleration, "a", given to an object by a force, "F", is proportional to the magnitude of the net force
Therefore, we have;
F ∝ a
The constant of proportionality is given as the mass, "m", of the object, therefore, we have;
F = m × a
The acceleration given to a 2 kg mass by a 2-N net force is given therefore, given as follows;
2 N = 2 kg × a
a = 2 N/(2 kg) = 1 m/s²
The acceleration, "a", caused by a net force of 2 N on a 2 kg mass is a = 1 m/s².
Distance is indeed a scalar amount that also refers to "<em><u>how the ground an object has encased</u></em>", and the Displacement is a vector thing that leads "<em><u>to the extent to which an object is located</u></em>", and the further calculation can be defined as follows:
Given:
distance= 70 miles
displacement = 20 miles
- Displacement formula:
- Distance formula:
Please find the graph in the attached file.
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Answer:
α = 13.7 rad / s²
Explanation:
Let's use Newton's second law for rotational motion
∑ τ = I α
we will assume that the counterclockwise turns are positive
F₁ 0 + F₂ R₂ - F₃ R₃ = I α
give us the cylinder moment of inertia
I = ½ M R₂²
α = (F₂ R₂ - F₃ R₃)
let's calculate
α = (24 0.22 - 13 0.10) 2/12 0.22²
α = 13.7 rad / s²