Answer:
(a) 140 F
(b) The temperature rise at the point where the heat is dumped is 2.51 degC
Explanation:
(a) Considering T1 the temperature of input of the first engine, T2 the temperature of the exhaust of the first engine (and input of the second engine) and T3 the exhaust of the second engine, if both engines have the same efficiency we have:
The temperatures have to be expressed in Rankine (or Kelvin) degrees
(b) The Carnot efficiency of the cycle is
If the efficiency of the plant is 60% of the Carnot efficiency, we have
The heat used in the plant can be calculated as
And the heat removed to the heat sink is
If the flow of the river is 165 m3/s, the heat per volume in the sink is
Considering a heat capacity of water C=4.1796 kJ/(kg*K) and a density ρ of 1000 kg/m3, the temperature rise of the water is
Answer:
=final temperature
Explanation:
In the question specific heat of water is not given but we should know the value of that and it 4.18Jg∘C
Specific heat means how much heat is required to increase the temperature of 1 gram of substance that substance by 1∘C .
Equation between heat lost or gain and the change in temperature.
q=m⋅c⋅ΔT , where
q - the amount of heat
m - the mass of the sample
c - specific heat of sample
ΔT - change in temperature
put all the given value into this ,
=final temperature.
Explanation:
1 ) Temperature of Venus in Kelvins = 757 Kelvins
Temperature of Venus in degrees Celsius =
2 ) Temperature on Mercury at night = 
Temperature on Mercury at night in degree Celsius = 167.22° C
Answer:
There should only be one chemical reaction, this is because toasting the bread is not only using heat, but you cannot untoast the bread, and also theres a reaction with the amino acids and sugar in bread when it's cooked. I hope this helps you! :)
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
