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Nuetrik [128]
3 years ago
5

Which statement is true of the electromagnetic spectrum?

Physics
2 answers:
Stels [109]3 years ago
6 0

Answer:

The lower the radiant energy, the lower frequency and the longer the wavelength.

Evgen [1.6K]3 years ago
3 0

Answer:

The lower the radiant energy, the lower the frequency and the longer the wave length. This is the correct answer.

Explanation:

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Find the pressure exerted on the floor by a 100N box whose bottom area is 40cm x<br> 50cm.
Mazyrski [523]

<u>Answer:</u>

Pressure exerted = 500 Pa

<u>Explanation:</u>

The formula for pressure is as follows:

Pressure = \frac{Force \space\ applied}{Area}

In this case,

Force applied = 100N

Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²

Substituting these values into the formula:

Pressure = \frac{100}{0.2}

⇒ Pressure = 500 Pa

3 0
2 years ago
Read 2 more answers
An athlete stretches a spring an extra 40.0 cm beyond its initial length. How much energy has he transferred to the spring, if t
notsponge [240]

Answer:

<h2>b) 4230 J </h2>

Explanation:

Step one:

given data

extension= 40cm

Spring constant K= 52.9N/cm

Step two:

Required

the Kinetic Energy KE

the expression to find the kinetic energy is

KE= 1/2ke^2

substituting our data we have

KE= 1/2*52.9*40^2

KE=0.5*52.9*1600

KE= 42320Joules

<u>The answer is b) 4230 J </u>

4 0
3 years ago
A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction be
SVEN [57.7K]
The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
7 0
3 years ago
What is a fact about incline planes?
SVETLANKA909090 [29]
They are incline hope this helps!
8 0
3 years ago
A pair of narrow slits, separated by 1.8 mm, is illuminated by a monochromatic light source. Light waves arrive at the two slits
Nastasia [14]

Answer:

750 nm

Explanation:

d  = separation of the slits = 1.8 mm = 0.0018 m

λ = wavelength of monochromatic light

D  = screen distance = 4.8 m

y = position of first bright fringe = \frac{1cm}{5 fringe} = \frac{0.01}{5} = 0.002 m

n  = order = 1

Position of first bright fringe is given as

y = \frac{nD\lambda }{d}

0.002 = \frac{(1)(4.8)\lambda }{0.0018}

λ = 7.5 x 10⁻⁷ m

λ = 750 nm

3 0
3 years ago
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