Answer:
V₂ = 1.86 L
Explanation:
Given data:
Initial volume = 4.30 L
Initial pressure = 1 atm
Initial temperature = 273.15 K
Final temperature = 302 K
Final volume = ?
Final pressure = 2.56 atm
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂
/T₁ P₂
V₂ = 1 atm ×4.30 L × 302 K / 273.15 K × 2.56 atm
V₂ = 1298.6 atm.L.K / 699.26 K.atm
V₂ = 1.86 L
Answer: -
1.71 cm
Explanation: -
Density of aluminium = 2.70 g /
Mass of aluminium = 13.5 g
We know density of a substance is the mass of the substance per unit volume.
Density = Mass / volume
Volume = Mass / density
Volume of aluminium = Mass of aluminium / Density of Aluminium
= 13.5 g / 2.70 g/
= 5
We know for a cube volume =
Length of the cube =
=
=1.71 cm
Thus if the density of aluminium is 2.70g/
and the cube of aluminum weights 13.5 grams, 1.71 cm is the length of the edge of the cube
Answer:
Common uses of oxygen include production of steel, plastics and textiles, brazing, welding and cutting of steels and other metals, rocket propellant, oxygen therapy, and life support systems in aircraft, submarines, spaceflight and diving.
Explanation:
Oxygen is used to degrade hydrocarbon compounds, which are broken apart by heating them. This is used to create combustion that usually liberates water and carbon dioxide, but can also produce the hydrocarbons acetylene, propylene and ethylene. Oxygen is used in sewage-treatment and water-purification plants.
Answer:
<u>0</u><u>.</u><u>2</u><u>1</u><u>7</u> ×2. =9.86×10moles
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