The answer is B to prevent condensation from forming on the agar surface
Answer: Volume of 1g of pure gold 
Given;
Density of a pure gold=19.3 
Mass of a pure gold =1g
To find:
Volume of 1g of pure gold
Solution:
According to the formula,
Density= Mass/Volume

Where
=density of pure gold
m=mass of pure gold
v=volume of pure gold
From the above equation volume can be calculated as

Substitute the values of mass and density value in the above equation


Result:
Thus the volume of 1g of pure gold is 
Answer:
<em>Well, Your best answer will be is 2H+ + 2OH- -> 2H2O but you have to reduce it to H+ + OH- -> H2O. </em><em>Good Luck!</em>
The chemical name is ferric oxide or iron (III) oxide or hematite. We can found it naturaly as a magnetite, mineral.