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3 years ago

How is fiber important to the body?

1 answer:

4 0

Dietary fiber increases the weight and size of your stool and softens it. A bulky stool is easier to pass, decreasing your chance of constipation. If you have loose, watery stools, fiber may help to solidify the stool because it absorbs water and adds bulk to stool. Helps maintain bowel health.

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Which of the following sets represents a pair of isotopes? (2 points) Question 6 options: 1) 35Cl and 37Cl 2) 40Ar and 40K 3) O2

nikitadnepr [17]

Isotope - the same element, but different atomic mass so 1)35 Cl and 37 Cl

4 0

3 years ago

A Venus Flytrap is a carnivorous plant, meaning it undergoes photosynthesis for food but also consumes insects for nutrients. In

nasty-shy [4]

Answer:

the food kingdom

Explanation:

look kid i just need some points socratic will help with

ur answer

5 0

3 years ago

Read 2 more answers

stiks02 [169]

Answer:

An organ is a part of the body that carries out its main function. Most organs are made out of tissues.

Explanation:

6 0

3 years ago

Read 2 more answers

There are many minerals which contain silver. A 2.00 g sample of one of these, stephanite, is placed in water and all of its sil

Nata [24]

Answer:

68.3%

Explanation:

First, let us look at the equation of reaction involving silver and magnesium chloride:

2Ag + MgCl2 ----> 2AgCl + Mg

1 mole of MgCl2 is required to precipitate 2 moles of Ag completely from the solution. That is a ratio of 1 to 2.

Now, mole of MgCl2 used to precipitate all the Ag

= molarity x volume

= 2.19 M x 2.89/1000

= 0.0063291 mole

Since 1 mole of MgCl2 would always require 2 moles of Ag, 0.0063291 mole will therefore require:

0.0063291 x 2 = 0.0126 mole of Ag

This means that 0.0126 mole of Ag is present in stephanie.

Mass of silver in stephanie = mole x molar mass

= 0.0126 x 107.8682

= 1.365 g

Thus, 1.365 g of silver is present in 2.00 g sample of stephanie.

Mass percent of silver in stephanie = 1.365/2.00 x 100

= 68.25% = 68.3% to the correct number of significant figure.

4 0

3 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

6 0

3 years ago