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andrey2020 [161]
3 years ago
5

How is fiber important to the body?

Chemistry
1 answer:
ale4655 [162]3 years ago
4 0
Dietary fiber increases the weight and size of your stool and softens it. A bulky stool is easier to pass, decreasing your chance of constipation. If you have loose, watery stools, fiber may help to solidify the stool because it absorbs water and adds bulk to stool. Helps maintain bowel health.
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Calculate the mass of nitrogen dissolved at room temperature in an 86.0 L home aquarium. Assume a total pressure of 1.0 atm and
Andrew [12]

Answer:

Mass of nitrogen gas dissolved= 1.1732 grams

Explanation:

According to Dalton's Law of partial pressure:

P_{N_2}=P_{Total}X_{N_2}

Where,

P_{N_2} is the partial pressure of nitrogen

P_{Total} is the Total pressure

X_{N_2} is the mole fraction of nitrogen

Given :

Total pressure  = 1.0 atm

Mole fraction of nitrogen = 0.78

Partial pressure of nitrogen:

P_{N_2}=1.0\times 0.78 atm

<u>Partial pressure of nitrogen = 0.78 atm</u>

According to Henry's law:

Solubility = Henry's constant (k)×Partial pressure

k = 6.26×10⁻⁴ mol/L-atm

Thus,

<u>Solubility of nitrogen = 6.26×10⁻⁴ mol/L-atm×0.78 atm = 4.8828×10⁻⁴ mol/L</u>

Given: Volume = 86.0 L

So, Moles of nitrogen gas dissolved:

Moles = Solubility (Concentration dissolved)×Volume

<u>Moles = 4.8828×10⁻⁴ mol/L×86.0 L = 0.0419 moles</u>

Also,

moles=\frac{Mass(m)}{Molar\ mass (M)}

Mass\ of\ nitrogen=moles\times {Molar\ mass}

Molar mass of nitrogen gas = 28 g/mol

So,

<u>Mass of nitrogen gas dissolved = 0.0419 moles×28 g/mol = 1.1732 grams</u>

6 0
4 years ago
The ability to conduct heat is an example of a chemical property. true or false
FrozenT [24]
False the ability to conduct heat is a physical property
7 0
3 years ago
Lysosomes are important for<br> digestion<br> cell division<br> reproduction<br> protein synthesis
KiRa [710]
It’s important for digestion.
7 0
3 years ago
Read 2 more answers
The solubility product of calcium fluoride (CaF2(s); fluorite) is 310-11 at 25C. Could a fluoride concentration of 1.0 mg L-1
Finger [1]

The given question is incomplete. The complete question is as follows.

The solubility product of calcium fluoride () is  at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?

Explanation:

Reaction equation for the given chemical reaction is as follows.

       CaF_{2} \rightleftharpoons Ca^{2+} + 2F^{-}

Therefore, expression for K_{sp} will be as follows.

        K_{sp} = [Ca^{2+}][F^{-}]^{2}

                     =

Also, moles of  per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]

                = \frac{1.0 \times 10^{-3}}{19.0}

               = 5.263 \times 10^{-5} mol

Hence,    [F^{-}] = \frac{\text{moles of F^{-}}{volume}

                       = \frac{5.263 \times 10^{-5}}{1}

                      =  M

Now, moles of  per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]

            = \frac{200 \times 10^{-3}}{40.1}

           =  M

Also,   [Ca^{2+}] = \frac{moles of Ca^{2+}}{volume}

                      = \frac{4.988 \times 10^{-3}}{1}

                     =  M

Hence, ionic product =

                 = (4.988 \times 10^{-3}) \times (5.263 \times 10^{-5})^{2}

                = 1.38 \times 10^{-11}

As, the ionic product is less than the K_{sp}, this means that the fluoride will be soluble in water containing the calcium.

4 0
3 years ago
A graduated cylinder contains 20.0 mL of water. After a rock is placed in the cylinder, the level rises as shown below. What is
Zielflug [23.3K]
The answer will be 14^3 cm
6 0
3 years ago
Read 2 more answers
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