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3 years ago

8

'If you increase the frequency of a sound wave four times, what will happen to its speed?

1 answer:

Firlakuza [10]3 years ago

8 0

The answer is c i did this

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Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5x10 to the third power kg of air?

valentinak56 [21]

Note: 2.5 * 10^3 kg = 2.5 * 10^3 * 10^3 = 2.5 * 10 ^6 g, Because 1 kg = 10^3 g

This is simple proportion

1.80 grams of air has a volume of 1 liter.

1 gram of air would have a volume of (1/1.8) liter

Therefore, 2.5 * 10^6 g would have: 2.5*10^6 * (1/1.8) = 1.3888 * 10^6 liters of air.

5 0

3 years ago

The distance between two particles is 2 centimeters. If the distance is increased to 4 centimeters, the force will be ?

postnew [5]

Answer:

The new force is 1/4 of the previous force.

Explanation:

Given

$Initial\ Distance = 2cm$ ---- $r_1$

$New\ Distance = 4cm$ --- $r_2$

Required

Determine the new force

Let the two particles be q1 and q2.

The initial force F1 is:

$F_1 = \frac{kq_1q_2}{r_1^2}$ --- Coulomb's law

Substitute 2 for r1

$F_1 = \frac{kq_1q_2}{2^2}$

$F_1 = \frac{kq_1q_2}{4}$

The new force (F2) is

$F_2 = \frac{kq_1q_2}{r_2^2}$

Substitute 4 for r2

$F_2 = \frac{kq_1q_2}{4^2}$

$F_2 = \frac{kq_1q_2}{4*4}$

$F_2 = \frac{1}{4}*\frac{kq_1q_2}{4}$

Substitute $F_1 = \frac{kq_1q_2}{4}$

$F_2 = \frac{1}{4}*F_1$

$F_2 = \frac{F_1}{4}$

The new force is 1/4 of the previous force.

3 0

3 years ago

What is the total magnification for each lens setting on a microscope with 15x oculars and 4x, 10x, 45x, and 97x objectives lens

KengaRu [80]

Answer:

M = 60x

M = 150x

M = 675x

M = 1455 x

Explanation:

In a microscope the total magnification is found by multiplying the magnification of the ocular (eye piece) and objective lens.

$m_e$ =Ocular magnification = 15x

$m_o$ =Objective magnification = 4x

Total magnification

$M=m_e\times m_o\\\Rightarrow M=15\times 4\\\Rightarrow M=60x$

M = 60x

$M=m_e\times m_o\\\Rightarrow M=15\times 10\\\Rightarrow M=150x$

M = 150x

$M=m_e\times m_o\\\Rightarrow M=15\times 45\\\Rightarrow M=675x$

M = 675x

$M=m_e\times m_o\\\Rightarrow M=15\times 97\\\Rightarrow M=1455x$

M = 1455 x

7 0

3 years ago

Using a common metric ruler, you measure the separation distance between two Al spheres from center to center to be 2.3 cm. What

Reptile [31]

Answer: 0.5 mm

Explanation: The smallest division that a common ruler has is 1 mm so any measurement taken is approximately accurate to a mm.

Uncertainty of any measuring instrument is the inaccuracy or lost of precision that occur due to its less divisions in an instrument

Uncertainty= Least Count /2

Uncertainty= 1 mm /2

Uncertainty= 0.5 mm

it means that measurement can be 2.3cm ± 0.5mm

8 0

3 years ago

GIVING BRAINLIEST PLEASE HELP!!

alisha [4.7K]

Answer:

c is the right answer is it

6 0

3 years ago