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Mashcka [7]
2 years ago
15

What elements react with mercury?

Chemistry
1 answer:
garri49 [273]2 years ago
7 0

fluorine, F2, chlorine, Cl2, bromine, Br2, or iodine, I2

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How many grams of NaNO3 in 165 grams of H2O at 20°C would fully dissolve?
Fantom [35]

Answer: birchbox

Explanation:

6 0
2 years ago
If heat transfers from the system (solute) to the surroundings (solvent), then AH is
balu736 [363]

Answer:

B) exothermic.

Explanation:

Hello!

In this case, we need to keep in mind that exothermic reactions release heat, so they increase the temperature as the final energy is less than the initial energy; in contrast, endothermic reactions absorb heat, so they decrease the temperature as the final energy is greater than the initial energy.

In such a way, when a dissolution process shows off a negative enthalpy of dissolution, we infer it is an exothermic process due to the aforementioned; therefore, the answer is:

B) exothermic .

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3 0
3 years ago
Sugar dissolving in warm water is chemical or phyiscal change
BlackZzzverrR [31]
Hey there! Great question;) Answer:Physical change Explanation: When sugar mixes with water, at the end, the chemical formulas are the same. Nothing has changed! I hope this helps;)
5 0
3 years ago
When does a phyisical change occur?
ioda
Physical changes occur when objects or substances undergo a change that does not change their chemical composition. This contrasts with the concept of chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances.
6 0
2 years ago
A particular sample of pure iron requires 0.612 kJ of energy to raise its temperature from 30.°C to 51°C. What must be the mass
mixas84 [53]

Answer:

m = 65.637 g

Explanation:

Heat = 0.612 kJ = 612 J ( Converting to J by multiplying by 1000)

Initial Temperature =  30.°C

Final Temperature = 51°C

Temperature change = Final Temperature - Initial Temperature = 51 - 30 = 21°C

Mass = ?

The relationship between these quantities is given by the equation;

H = mCΔT

where c = 0.444 J/g°C

Inserting the values in the equation;

612 = m *  0.444 * 21

m = 612 / (0.444 * 21)

m = 65.637 g

3 0
2 years ago
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