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3 years ago

What are two variables that affect kinetic energy

Chemistry

1 answer:

zubka84 [21]3 years ago

7 0

The answer for the following questions is explained below.

Explanation:

The two variables that affect kinetic energy are:

mass and
velocity

velocity - The faster an object moves,the more the kinetic energy it has.

mass - Kinetic energy increases as mass increases

The kinetic energy of an object depends on both its mass and its velocity

Kinetic energy increases as mass increases

For example,think about rolling a bowling ball and a golf ball down a bowling lane at same velocity

Here,the bowling ball has more mass than the golf ball

Therefore you use more energy to roll the bowling ball than to roll the golf ball

The bowling ball is more likely to knock down the pins because it has more kinetic energy than the golf ball

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1 Calcium carbonate breaks down on heating to produce calcium oxide and carbon dioxide gas.

Alborosie

Answer: See below

Explanation:

1. a) 0.15 moles calcium carbonate (15g/100g/mole)

b) 0.15 moles CaO (molar ratio of CaO to CaCO3 is 1:1)

c) 8.4 grams CaO (0.15 moles)*(56 grams/mole)

2. a) 0.274 moles Na2O (17g/62 grams/mole)

b) 46.6 grams NaNO3 (2 moles NaNO3/1 mole Na2O)*(0.274 moles Na2O)*(85 g/mole NaNO3)

7 0

2 years ago

For the reaction below, initially the partial pressure of all 3 gases is 1.0atm. . 2NH3(g)--> N2(g) + 3H2(g) K, 0.83 1. When

erma4kov [3.2K]

Answer:

The reaction would shift toward the reactants

When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm

Explanation:

For the reaction:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where K is defined as:

$K = \frac{P_{N_{2}}*P_{H_2}^3}{P_{NH_3}^2} = 0.83$

As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:

$Q = \frac{1atm*{1atm}^3}{1atm^2} = 1$

As Q > K, <em>the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.</em>

Thus, there are true:

<h3>The reaction would shift toward the reactants</h3><h3>When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm</h3>

<em />

4 0

3 years ago

Who ever gets right gets brainliest

grandymaker [24]

Answer:

it's subduction

Explanation:

i know this because I just do lol

4 0

3 years ago

How many moles of hydrogen are required to make 32 moles of water?

NNADVOKAT [17]

You multiply 32 by 2, since there are two hydrogens in every water molecule.

7 0

3 years ago

Read 2 more answers

The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha

zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$25.9 = x*10.0$

$25.9 = 10.0\:x$

$10.0\:x = 25.9$

$x = \dfrac{25.9}{10.0}$

$\boxed{x = 2.59}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{53.3}{2^{2.59}}$

$m \approx \dfrac{53.3}{6.021}$

$\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

3 0

3 years ago