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CaHeK987 [17]
3 years ago
12

Explain how barometric pressure is measured.

Chemistry
1 answer:
Lisa [10]3 years ago
6 0

Answer:

inches of mercury (inHg or “Hg) or millibars.

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In your own words what is equilibrium?
fenix001 [56]

Answer:

when the forward and reverse reactions occur at equal rates.

chemical reaction is in equilibrium when the concentrations of reactants and products are constant - their ratio does not vary.

8 0
3 years ago
Meet /svc-jgyu-fii<br>join​
arsen [322]

Answer:

what are we doing there???

bye, have a nice day!

5 0
3 years ago
- How much power does it take to lift a<br> 1,000 N load 10 m in 20 s?
Mariana [72]

Answer:

"500 Joule/sec" is the right answer.

Explanation:

The given values are:

Force,

F = 1000 N

Velocity,

s = 10 m

Time,

t = 20 s

Now,

The power will be:

=  \frac{Force\times Velocity}{Time}

On putting the values, we get

=  \frac{1000\times 10}{20}

=  \frac{10000}{20}

=  500 \ Joule/sec

5 0
3 years ago
The fuel used to power the booster rockets on space shuttles is a mixture of aluminum metal and ammonium perchlorate. The follow
pishuonlain [190]

Answer:

Therefore 373 mole of Al produce 746 mole of water.

Explanation:

Given reaction is

3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O

From the above reaction it is clear that 3 mole of Al produce 6 mole of water.

Therefore

3 mole of Al produce 6 mole of water.

1 mole of Al produce \frac{6}{3} mole of water.

373 mole of Al produce \frac{6\times 373}{3} mole of water.

                                      = 746 mole of water.

Therefore 373 mole of Al produce 746 mole of water.

7 0
3 years ago
Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?
dlinn [17]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles
  • O₂: 13 moles
  • CO₂: 8 moles
  • H₂O: 10 moles

Being:

  • C: 12 g/mole
  • H: 1 g/mole
  • O: 16 g/mole

The molar mass of the compounds that participate in the reaction is:

  • C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
  • H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles* 58 g/mole= 116 g
  • O₂: 13 moles* 32 g/mole= 416 g
  • CO₂: 8 moles* 44 g/mole= 352 g
  • H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10}   }{116 grams of C_{4}H_{10}}

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, <u><em>reagent O₂ will be consumed first.</em></u>

3 0
2 years ago
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