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Sliva [168]
3 years ago
14

Assuming that the following three variables have already been declared, which variable will store a Boolean value after these st

atements are executed?
choice = true;
again = "false";
result = 0;

a. choice
b. again
c. result
d. none of these are Boolean variables
Engineering
1 answer:
Yuki888 [10]3 years ago
5 0

Answer:

C

Explanation:

Boolean Algebra deals with either a one or a zero and how to manipulate them in computers or elsewhere. The "choice" option may not work, since for text it must be enclosed in quotation marks, usually. For "again," it's text and not a 1 or 0. So, the answer is C, since this is a 0.

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A hollow steel shaft with and outside diameter of (do)-420 mm and an inside diameter of (di) 350 mm is subjected to a torque of
-Dominant- [34]

Answer:

a.  \tau=51.55 MPa

b.\tau=42.95MPa

c.\theta=7.67\times 10^{-3} rad.

Explanation:

Given: D_i=350 mm,D_o=420 mm,T=300 KN-m ,G=80 G Pa

We know that

\dfrac{\tau}{J}=\dfrac{T}{r}=\dfrac{G\theta}{L}

J for hollow shaft J=\dfrac{\pi (D_o^4-D_i^4)}{64}

(a)

 Maximum shear stress \tau =\dfrac{16T}{\pi Do^3(1-K^4)}

      K=\dfrac{D_i}{D_o}⇒K=0.83

\tau =\dfrac{16\times 300\times 1000}{\pi\times 0.42^3(1-.88^4)}

   \tau=51.55 MPa

(b)

We know that \tau \alpha r

So \dfrac{\tau_{max}}{\tau}=\dfrac{R_o}{r}

\dfrac{51.55}{\tau}=\dfrac{210}{175}

\tau=42.95MPa

(c)

\dfrac{\tau_{max}}{R_{max}}=\dfrac{G\theta }{L}

\dfrac{51.55}{210}=\dfrac{80\times 10^3\theta }{2500}

\theta=7.67\times 10^{-3} rad.

8 0
4 years ago
Find the remaining trigonometric function of 0 if
amm1812

Answer:

Hope this will help you

have a great day

8 0
3 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
Ilya [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

8 0
3 years ago
Write a single statement to print: user_word,user_number. Note that there is no space between the comma and user_number. Sample
kykrilka [37]

Answer:

cout<<"''<<user_word<<"' "<<user_number;

Explanation:

The above question was answered using C++ programming language.

The keyword cout represents print and it carries out print operation only.

It prints all variable in front of it.

Assume the values of user_word and user_number to be Charles and 20, respectively.

The output of the above instruction would be

'Charles' 20 just as it is in the sample output in the question.

In java programming language, it is

System.out.print("'"+user_word+"' "+user_number);

In Qbasic, it is

PRINT "'"+user_word+"' "+ user_number

8 0
3 years ago
Consider the following set of processes, with the length of the CPU burst given in milliseconds:Process Burst Time PriorityP1 2
Iteru [2.4K]

Answer and Explanation:

The answer is attached below

6 0
3 years ago
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