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Hey There!</h2><h2>
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Answer:</h2>
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"The restoring force is directly proportional to the displacement from the equilibrium position under elastic limits"
Consider a block on a horizontal, frictionless surface is connected to a spring. If the spring is either stretched or compressed a small distance x from its mean position, it exerts on a block a force:
K is positive constant called the force\spring constant of the spring. Negative sign indicates that F and x always have opposite directions with reference x-axis as the direction of force is always towards mean position.
Using the magnitude of force, in hooke's law,
The units of K are given as,
The dimension of K is,
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<u>DATA</u>:
Force = F = 2.5N
Displacement = x = 4.0cm
Spring constant = k = ?
Final displacement = x = 12 cm
Load = F = ?
<u>SOLUTION</u>:
F = -kx
substitute the variable,
2.5 = k x 4
Rearrange the equation,
k =
Use the spring constant with the extension 12cm to find the load,
F = kx
F = (0.625) x (12)
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>