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gregori [183]
4 years ago
11

a runner increases her speed from 3.1 m/s to 3.5 m/s during the last 15 seconds of her run, what was her acceleration during her

big push to the finish ?
Physics
2 answers:
Rama09 [41]4 years ago
5 0
Acceleration = velocity/time
A= 3.5m/s/15s
A= 0.23m/s^2
goblinko [34]4 years ago
4 0

Answer:

0.027m/s²

Explanation:

Acceleration (in its simpler form) is defined as the change in velocity divided by the interval of time in which occurred that change. Mathematically:

a=\frac{v_{2}-v_{1} }{t}

Where:

v_{1}: initial velocity

v_{2}: final velocity

t: time needed to that increase in velocity

Plugging the given values in the equation:

a=\frac{3.5m/s-31m/s}{15s}

a=\frac{0.4m/s}{15s}

<em>a= 0.027m/s²</em>

So, her acceleration during her big push was 0.027m/s²

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Answer: The correct answer is A). Animal burrow because burrow fossils represent the preserved byproducts of behavior rather than physical remains, they are considered a kind of trace fossil. One common kind of burrow fossil is known as Skolithos, and the similar Trypanites, Ophiomorpha and Diplocraterion.

4 0
3 years ago
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S/REF No. Date If the load distance of a level is 20 cm and effort distance is 6ocm, calculate the amount of effort required to
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3 years ago
Two long parallel wires are separated by forty centimeters and carry oppositely-directed currents of ten amperes. Find the magni
Softa [21]

Answer:

1.04μT

Explanation:

Due to both wires have opposite currents, the magnitude of the total magnetic field is given by

B_T=\frac{\mu_o I}{2 \pi r_1}-\frac{\mu_o I}{2 \pi r_2}

I: electric current = 10A

mu_o: magnetic permeability of vacuum = 4pi*10^{-7} N/A^2

r1: distance from wire 1 to the point in which B is measured.

r2: distance from wire 2.

The distance between wires is 40cm = 0.4m. Hence, r1=0.2m r2=0.6m

By replacing in the formula you obtain:

B_T=\frac{(4\pi *10^{-7}N/A^2)(10A)}{2\pi}(\frac{1}{0.4m}-\frac{1}{0.6m})=1.04*10^{-6}T =1.04\mu T

hence, the magnitude of the magnetic field is 1.04μT

4 0
4 years ago
What would happen if the moon’s horizontal motion sped up too much
antiseptic1488 [7]
Idk


I
I
I
I


R
D
D
D
D
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I
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7 0
4 years ago
(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin
Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

For the small object, p=2*6.71, which gives us p=13.42 kg*m/s

For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

5 0
3 years ago
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