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gregori [183]
3 years ago
11

a runner increases her speed from 3.1 m/s to 3.5 m/s during the last 15 seconds of her run, what was her acceleration during her

big push to the finish ?
Physics
2 answers:
Rama09 [41]3 years ago
5 0
Acceleration = velocity/time
A= 3.5m/s/15s
A= 0.23m/s^2
goblinko [34]3 years ago
4 0

Answer:

0.027m/s²

Explanation:

Acceleration (in its simpler form) is defined as the change in velocity divided by the interval of time in which occurred that change. Mathematically:

a=\frac{v_{2}-v_{1} }{t}

Where:

v_{1}: initial velocity

v_{2}: final velocity

t: time needed to that increase in velocity

Plugging the given values in the equation:

a=\frac{3.5m/s-31m/s}{15s}

a=\frac{0.4m/s}{15s}

<em>a= 0.027m/s²</em>

So, her acceleration during her big push was 0.027m/s²

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How might you use a rope and pulley to move a wagon up a ramp?
sleet_krkn [62]
You could attach the pulley to a secure object on the top of the ramp, and crank the pulley to bring the wagon up said ramp into a loading bay perhaps, or a track. 

Hope I helped. 
7 0
3 years ago
Un movil pasa por el punto A en direccion hacia B (350cm más adelante) y, luego, sigue hasta el punto C. Sabiendo que pasa por B
xeze [42]

Explanation:

PRIMERO HACES EL RECUENTO DEL TIEMPO Y LO CONVIERTES EN

SEGUNDOS Y ENTONCES

<em>t</em> = 227 s      t_{AB} = 227 S - 38 s = 189 s

t_{BC} = 38 s

LUEGO USANDO LA ECUACIÓN DE GALILEO GALILEI SSUPONIENDO

QUE EL MOVIL VIAJA A VELOCIDAD CONSTANTE

<em>v</em> = 3.50 m/189 s = 0.0185 m/s

PARA LA DISTANCIA NTRE B Y C

x_{BC} = 0.0185 m/S( 38 s) = 0.703 m

LA HORA EN QUE EL MOVIL PASA POR A ES

11:43:15 - 38 s - 189 s = 11:39:29

6 0
3 years ago
How much time does it take light from a flash camera to reach a subject 6.0 meters across a room in scientific notation?
wariber [46]

The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

<u>Explanation:</u>

<u>Given</u>

t=?

d=6m

v=3*10^8 m/s

we  have,  v=d/t

here t=d/v

t=6m/3*10^8 m/s

v=2*10^-8 m/s

The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

<u></u>

6 0
3 years ago
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it
levacccp [35]

Answer:

46620\ \text{N}

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Normal force at the point will be

N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}

The force exerted on the track is 46620\ \text{N}.

8 0
3 years ago
Which of the following can be determined by studying the spectrum of a star?
Alex73 [517]
The right answer is 
  
all of the above 
 
good luck

3 0
3 years ago
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