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steposvetlana [31]
3 years ago
14

A student uses visible spectrophotometry to determine the concentration of CoCl2(aq) in a sample solution. First the student pre

pares a set of CoCl2(aq) solutions of known concentration. Then the student uses a spectrophotometer to determine the absorbance of each of the standard solutions at a wavelength of 510nm and constructs a standard curve. Finally, the student determines the absorbance of the sample of unknown concentration.
The original solution used to make the solutions for the standard curve was prepared by dissolving 2.60g of CoCl2 (molar mass 130.g/mol) in enough water to make 100.mL of solution. What is the molar concentration of the solution?

A) 0.200 mol
B) 0.500 mol
C) 1.00 mol
D) 5.00 mol
Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer:

A

Explanation:

2.60 g of CoCl2 was dissolved in water to make 100 mL of solution.

Number of moles of CoCl2 dissolved = mass/molar mass

                                = 2.60/130

                                   = 0.02 mole

Molar concentration of solutions = number of moles/volume (dm3)

                          = 0.02/0.1

                            = 0.200 M

Hence, the molar concentration of thesolution is 0.200 molar.

Correct option = A

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Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}

To calculate the value of k which is a dependent variable for the above equation ; we have:

k = \dfrac{-In(1-0.40)}{200^{2.5}}

k = 9.030 \times 10 ^{-7}

The time needed for 50% transformation can be determined as follows:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}

t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}

= 200.00183 min

The rate of reaction for Avrami equation is:

rate = \dfrac{1}{t_{0.5}}

rate = \dfrac{1}{200.00183}

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

8 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
You inoculate a bacterium into three tubes of nutrient broth medium containing added salt: 0.5% NaCl, 5% NaCl, and 15% NaCl. Aft
g100num [7]

Answer:

Halophile.

Explanation:

Halophile microorganisms are microorganisms that  require very large amounts of NaCl. If the concentration of NaCl is very little, there will be no growth. Ih this case, given that it grows between 5% and 15%, it can be considered a moderate halophile.

5 0
3 years ago
Formation of magnesium chloride​
Shkiper50 [21]

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5 0
3 years ago
PLEASE HELP
dalvyx [7]

It has a -1 charge, so it would gain one!

5 0
3 years ago
Read 2 more answers
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