Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.

where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
![240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]](https://tex.z-dn.net/?f=240%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A%28%5Cfrac%7B1h%7D%7B3600s%7D%20%29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D66.67%5Bm%2Fs%5D)
Now replacing:
![66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]](https://tex.z-dn.net/?f=66.67%20%3D%200%20%2Ba%2A2%5C%5Ca%20%3D%2033.33%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
![925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]](https://tex.z-dn.net/?f=925000%3Dm%2A33.33%5C%5Cm%20%3D%20925000%2F33.33%5C%5Cm%20%3D%2027752.7%20%5Bkg%5D)
Answer:
<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>
Explanation:
<u>Electric Power in a Resistor</u>
Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:
V = R.I
The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:

Solving the first equation for I:

Substituting in the second equation:

Simplifying:

Solving for V:

The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:


V = 4.85 V
The maximum voltage that can be applied without damaging the resistor is 4.85 V
Answer:
balanced?
Explanation:
because if it wasn't moving that means they are pulling at a similar strength
Answer:
why is fraction called a necessary evil