The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.
<h3>
Frequency detected by the student</h3>
The observed frequency is determined by applying Doppler effect;
f' = f₀(v + v₀)/(v)
where;
- f' is the observed frequency
- v is speed of sound
- v₀ is the source speed
- f₀ is the original frequency
f' = 342(6 + 336)/(336)
f' = 348.1 Hz
Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.
Learn more about observed frequency here: brainly.com/question/10728818
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- The two types of grip in table tennis are <u>penhold grip</u> and <u>shakehand grip</u>.
- A <u>serve</u> is a stroke that starts a rally.
- A <u>receive</u> is a stroke to reply to a <u>serve</u>.
- A let is a <u>rally</u> of which the result is <u>not scored</u>.
- A point is a rally of which the result is scored.
<h3>What is table tennis?</h3>
Table tennis can be defined as an indoor sport and recreational activity in which two (2) or four (4) players hit a ping-pong ball back and forth on a table that is divided into halves by a low net, especially through the use of a small-solid bat (racket).
<h3>Types of grip in
table tennis.</h3>
Generally, there are two (2) main types of grip in table tennis and these include:
<h3>The
fundamental skills of table tennis.</h3>
Basically, there are four (4) fundamental skills used in table tennis and these are:
- Forehand drive
- Backhand drive
- Backhand push
- Forehand push.
Read more on table tennis here: brainly.com/question/17358010
EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Answer:
6.86 × 10²⁴ kg
Explanation:
The mass of the earth m = density of earth, ρ × volume of earth, V
m = ρV
The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m
Since m = ρV
m = ρ4πr³/3
So, substituting the values of the variables into the equation for the mass of the earth, m, we have
m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3
m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3
m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3
m = 6546105.64378π × 10¹⁸ kg/3
m = 20565197.400122 × 10¹⁸ kg/3
m = 6855065.8 × 10¹⁸ kg
m = 6.8550658 × 10²⁴ kg
m ≅ 6.86 × 10²⁴ kg