Question

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?

Answer 1

If you have a fraction, then the denominator (bottom) cannot equal 0, since it is impossible to divide by 0. Take a look at the function below.

$y=\frac{5}{x-2}$

If we plugged in 2 for x, we would end up with a denominator of 0, making x = 2 "extraneous."

(you can use this example to answer your question, with the denominator being x-2...any expression that evaluates to 0 when x = 2 would work)

Answer 2

x=2 should work

yay so only follow thw answer above