The distance below the top of the cliff that the two balls cross paths is 7.53 meters.
<u>Given the following data:</u>
- Initial velocity = 0 m/s (since the ball is dropped from rest).
<u>Scientific data:</u>
- Acceleration due to gravity (a) = 9.8
.
To determine how far (distance) below the top of the cliff that the two balls cross paths, we would apply the third equation of motion.
<h3>How to calculate the velocity.</h3>
Mathematically, the third equation of motion is given by this formula:

<u>Where:</u>
- U is the initial velocity.
- S is the distance covered.
Substituting the parameters into the formula, we have;

V = 24.25 m/s.
<u>Note:</u> The final velocity of the first ball becomes the initial velocity of the second ball.
The time at which the two balls meet is calculated as:

Time = 1.24 seconds.
The position of the ball when it is dropped from the cliff is calculated as:

Lastly, the distance below the top of the cliff is calculated as:

Distance = 7.53 meters.
Read more on distance here: brainly.com/question/10545161
Answer:
A. PMC tends to fit the construction purposes for which it was specifically designed.
Explanation:
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A staircase what makes it a lever is another objects used to displace the force better