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(a) 33.6 L of oxygen would be produced.
(b) 106 grams of 
would be needed
<h3>Stoichiometric calculations</h3>
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of 
produce 3 moles of 
. 1 mole of will, therefore, produce 1.5 moles of .
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of 
is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of requires 1 mole of .
Molar mass of = (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole = 1 x 106 = 106 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:
A) One that occurs on its own
Answer:
a. Kw = 1.0 × 10⁻¹⁴
Explanation:
a. Let's consider the self-ionization of water.
2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻
The ion-product of water (Kw) at 25 °C is:
Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴
c. Considering [H⁺] = [H₃O⁺] = 4.0 × 10⁻⁹ M, the concentration of OH⁻ is:
[OH⁻] = 1.0 × 10⁻¹⁴/[H₃O⁺] = 2.5 × 10⁻⁶ M
b. We can calculate the pOH using the following expression.
pOH = -log [OH⁻] = -log 2.5 × 10⁻⁶ = 5.6
d. We can calculate the pH using the following expression.
pH = -log [H⁺] = -log 4.0 × 10⁻⁹ = 8.4
