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DiKsa [7]
3 years ago
8

The first periodic table that was developed arranged elements in order of atomic number.

Chemistry
2 answers:
ziro4ka [17]3 years ago
3 0
Heyyy!!


Your answer is True.


Please mark it as brainliest.


Hope it helps you.
Akimi4 [234]3 years ago
3 0
Answer is false as first periodic table was developed arranged element according to atomic mass . it leaded to wrong place of some elementt
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Help please! Chem hw
DiKsa [7]
Hello!

GAS SOLUBILITY INCREASES:

• O2 in the blood of a person who is in a hyoerbaric chamber.

• The partial pressure of an anesthetic gas is increased.

• The temperature is decreased.


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• CO2 In a can of soda as it warms to room temperature.

• The pressure of a gas over a solvent is decreased.

I really hope this helped you! :)
6 0
3 years ago
Question 6(Multiple Choice Worth 2 points)
Rina8888 [55]
4.2 × 10²² atoms Al × (1 mol Al / 6.022 × 10²³) = moles Al

Last one: fraction 1 mole Al over 6.022 × 10²³ atoms Al
8 0
3 years ago
In 1 kilogram of pure water, the mass of hy drogen atoms is approximately 112 grams, or 0.112 kilograms. what is the energy equi
zlopas [31]
1.008x10^16 Joules. Technically a theory and not a law. but E=MC^2!
energy=mass ×speed of light squared.
J=kg×(m/s)^2
3 0
4 years ago
What is ΔG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.6 M and the concentration of B is 0.50
Galina-37 [17]

Answer:

The Gibbs free energy is -2997.83 kJ mol-1.

Explanation:

The change in Gibbs free energy of the reaction \Delta G can be calculated using the formula.

\Delta G = -RTlnK

WHere R = Gas constant = 8.314KJ/Kmol

T = the temperature of the reaction in Kelvin = (37.0 + 273) = 310K

K = Raio of molar concentration of the two reactants = 1.6/0.5 = 3.2

Therefore,

\Delta G = -8.314 \times 310 \times  ln (3.2) = -2997.83 kJ mol-1

Therefore the Gibbs free energy is -2997.83 kJ mol-1.

The negative sign indicates that the reaction is spontaneous.

4 0
3 years ago
Ch4(g) + h2o(g) 3h2(g) + co(g) enthalpy of formation of CH4
Aneli [31]

Answer:

Kc=[[CO][H2]3[CH4][H2O]

3.90=(0.30)(0.10)3[CH4]×0.02

[CH4]=0.023.90×0.30×(0.10)3=5.85×10−2 M

Thus, the concentration of methane in the mixture is 5.85×10−2 M.

4 0
3 years ago
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