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3 years ago

In beta decay, what is emitted?

Chemistry

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

In beta decay, an electron is emitted.

Explanation:

Beta decay is a type of particle decay in which beta radiation is emitted. That is, an unstable nucleon (proton or neutron) emits a beta particle.

There are two forms of decay or beta particles, β - and β +, which respectively emit an electron or a positron.

That is, beta particles are particles of mass and charge equal to the electron (β-) or positrons, whose mass is equal to the electron but of opposite charge (β +) resulting from the transformation of the neutrons or protons of the nucleus when it is found in an excited state.

Bingel [31]3 years ago

5 0

I'm pretty sure its an electron. I hope this helps! (:

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Answer:

2h+02=h20

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Is potassium fluoride a covalent bond or ionic bond

Ivahew [28]

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A covalent bond is the bond between two nonmetals.

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3 years ago

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Which of the following answers is true for the following statement?

Vsevolod [243]

it is either "aweak acid or a lousy (or very weak) acid"

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2 years ago

How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium

Pepsi [2]

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as $\text{Pb}^{2+}$ ions. The formula for a nitrate ion is ${\text{NO}_3}^{-}$ . The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each $\text{Pb}^{2+}$ ion in lead nitrate would pair up with two ${\text{NO}_3}^{-}$ ions. The formula for lead nitrate will be $\text{Pb}({\text{NO}_3})_2$ . Each formula unit of lead nitrate will contain one $\text{Pb}^{2+}$ ion and two ${\text{NO}_3}^{-}$ ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as $\text{Cr}^{3+}$ . Similarly, each $\text{Cr}^{3+}$ will pair up with three ${\text{NO}_3}^{-}$ ions. The formula for chromium (III) nitrate will be $\text{Cr}(\text{NO}_3})_3$ . Each formula unit of chromium (III) nitrate will contain one ${\text{NO}_3}^{-}$ ion and three ${\text{NO}_3}^{-}$ ions.

0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of ${\text{NO}_3}^{-}$ ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.

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3 years ago

What is meant by collision theory?

Tcecarenko [31]

Answer:

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2 years ago