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masya89 [10]
3 years ago
5

How does load transfer of space needle​

Engineering
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

The Space Needle is a cut away with minimal residual deflection due to load transfer.

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Given a manhole with the outlet invert elevation of 2605. A run of 48 inch pipe connects to the next manhole at an invert elevat
alexdok [17]

Answer:

Distance between manholes = 166.67 (Unit) (Approx)

Explanation:

Given:

Invert elevation = 2605

New Invert elevation = 2610

Grade % = 3% = 0.03

Find:

Distance between manholes

Computation:

Grade % = (Change in elevation)/Distance between objects

0.03 = (2610-2605)/Distance between manholes

0.03 = 5 / Distance between manholes

Distance between manholes = 166.67 (Unit) (Approx)

5 0
3 years ago
The application of technology results in human-made things called
Sergio039 [100]

Answer:

Internet of things

Explanation:

This is a good example where the application of technology results are applied to human made things.

Internet of things (IOT), involves the application of one technology results–the internet, embedded into devices such as refrigerator, television etc so as to send and receive data (digital instructions). Such applications of technology results has revolutionized the way we use "human made things".

8 0
4 years ago
An insulated 40 ft^3 rigid tank contains air at 50 psia and 580°R. A valve connected to the tank is now opened, and air is allow
Pachacha [2.7K]

Answer:

The answer is "\bold{W_{in} = 645.434573 \ Btu}".

Explanation:

Its air enthalpy is obtained only at a given temperature by A-17E.  

The solution from the carbon cycle is acquired:

\to \Delta U= W_{in}-m_{out}h_{out}=0\\\\\to W_{in} = (m_1 - m_2)h

           =\frac{Vh}{RT}(P_1- P_2)\\\\= \frac{40 \times 138.66}{0.3704\times 580}(50-25) Btu\\\\= \frac{5,546.4}{214.832}(25) Btu\\\\= 25.8173829(25) Btu\\\\ =645.434573 Btu

W_{in} = 645.434573 \ Btu

8 0
3 years ago
Water enters the pump of a steam power plant as saturated liquid at 20 kPa at a rate of 45 kg/s and exits at 6 MPa. Neglecting t
Natasha2012 [34]

Answer:

\dot W_{in} = 273.69\,kW

Explanation:

The pump is modelled after the First Law of Thermodynamics. A reversible process means that fluid does not report any positive change in entropy:

\dot W_{in} + \dot m \cdot (h_{in}-h_{out}) = 0

The properties of the fluid at entrance and exit are, respectively:

Inlet (Saturated Liquid)

P = 20\,kPa

T = 60.06\,^{\textdegree}C

h = 251.42\,\frac{kJ}{kg}

s = 0.8320\,\frac{kJ}{kg\cdot K}

Outlet (Subcooled Liquid)

P = 6000\,kPa

T = 60.06\,^{\textdegree}C

h = 257.502\,\frac{kJ}{kg}

s = 0.8320\,\frac{kJ}{kg\cdot K}

The power input to the pump is computed hereafter:

\dot W_{in} = \left(45\,\frac{kg}{s} \right)\cdot \left(257.502\,\frac{kJ}{kg} -251.42\,\frac{kJ}{kg} \right)

\dot W_{in} = 273.69\,kW

8 0
4 years ago
I need answers for this sheet please.
9966 [12]
The image it blank and I can’t see anything it’s all white
7 0
4 years ago
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