Answer:
32(molecular mass has no unit )
Explanation:
(16)(o2)
16×2
=32
Answer:
300.06 grams of glucose can be produced from a photosynthesis reaction that occurs using 10 moles of carbon dioxide.
Explanation:
I know what you're asking but I don't think the question is stated properly. Technically, an atom will not join with an "oxide" ion; i.e., the oxide ion is an atom of oxygen to which two electrons have been added. An oxide ion will add to 2 K ions or 1 Ca ion. The K ion has lost just one electron so it takes two of them to equal the 2- charge on the oxide ion whereas the Ca ion has lost two electrons and it takes only one of them to equal the charge on the oxide ion.
<u>Answer:</u>
<em>4.5 L water we have in litres (L).</em>
<em><u></u></em>
<u>Explanation:</u>

where
= Final T - Initial T
Q is the heat energy in calories
c is the specific heat capacity (for water 1.0 cal/(g℃))
m is the mass of water
Plugging in the values

So,
Volume of water = mass/density

=4.5 L (Answer)
Where is the chooses for you question