3 years ago

What type of device is a refrigerator?

Physics

1 answer:

Tamiku [17]3 years ago

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A heat pump that uses work to move heat

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1148.37401575 kg/m³

Explanation:

Volume of liquid in pipet

25.4 mL

Mass of liquid

$77.8760-48.7073=29.1687\ g$

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{29.1687}{25.4}\\\Rightarrow \rho=1.14837401575\ g/ml=1.14837401575\times 10^3=1148.37401575\ kg/m^3$

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wavelength = speed / frequency

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A 0.700-kg particle has a speed of 1.90 m/s at point circled A and kinetic energy of 7.20 J at point circled B. (a) What is its

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Answer:

a). $E_{kA}=1.2635 J$

b). $V_{B}=4.535\frac{m}{s}$

c). Δ $E_{t}=8.4635 J$

Explanation:

ΔE=kinetic energy

a).

$E_{kA}=\frac{1}{2}*m*v_{A} ^{2} \\ v_{A}=1.9 \frac{m}{s}\\ m=0.70kg\\E_{kA}=\frac{1}{2}*0.70kg*(1.9 \frac{m}{s})^{2} \\E_{kA}=1.2635 J$

b).

$E_{kB}=\frac{1}{2}*m*v_{B} ^{2}$

$V_{B}^{2}=\frac{E_{kB}*2}{m} \\V_{B}=\sqrt{\frac{E_{kB}*2}{m}} \\V_{B}=\sqrt{\frac{7.2J*2}{0.70kg}} \\V_{B}=4.53 \frac{m}{s}$

c).

net work= EkA+EkB

$E_{t}=E_{kA}+ E_{kB}\\E_{t}=1.2635J+7.2J\\E_{t}=8.4635J$

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3 years ago