At what temperature does ice melt at 101kPa?

A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose

Aloiza [94]

Answer:

2.6%

Explanation:

As, 1 ounce (oz) = 0.0625 pounds (lb)

Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb

Since, 1 oz = 0.0625 lb

⇒ 4 oz = 4×0.0625 = 0.25 lb

Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb

The amount of weight lost is equal to the difference of weight of the baby at birth and discharge.

Therefore, weight lost = 7.25 lb - 7.0625 lb = 0.1875 lb

Now, the percentage of weight lost by the baby is given by the amount of weight lost divided by the weight of the baby at birth.

Therefore, the percentage of weight lost = weight lost ÷ weight at birth = 0.1875 lb ÷ 7.25 lb × 100 = 2.6%

6 0

4 years ago

A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for

Rom4ik [11]

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of $Ga^{3+}$ as follows.

Moles of $Ga^{3+}$ solution = molarity × volume (L)

= 0.0440 M × 0.014 L

= 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

Total initial moles of EDTA = 0.0600 M × 0.025 L

= 0.0015

Therefore, moles of EDTA reacted with $V^{3+}$ will be as follows.

= 0.0015 - 0.000616

= 0.00088 moles

Since, we have supposed a 1 : 1 ratio between $V^{3+}$ and EDTA .

So, moles of $V^{3+}$ = 0.00088 moles

Now, we will calculate the molarity of $V^{3+}$ as follows.

Molarity of $V^{3+}$ solution = $\frac{\text{moles}}{\text{volume (L)}}$

= $\frac{0.00088 moles}{0.057 L}$

= 0.015 M

Thus, we can conclude that the original concentration of the $V^{3+}$ solution is 0.015 M.

4 0

3 years ago

Cylinder of air at 1.5 atm of pressure is kept at room temperature while a piston compresses the air from 40 l down to 10 ml. wh

djyliett [7]

The new pressure, P₂ is 6000 atm.

<h3>Calculation:</h3>

Given,

P₁ = 1.5 atm

V₁ = 40 L = 40,000 mL

V₂ = 10 mL

To calculate,

P₂ =?

Boyle's law is applied here.

According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.

PV = constant

Therefore,

P₁V₁ = P₂V₂

Put the above values in the equation,

1.5 × 40,000 = P₂ × 10

P₂ = 1.5 × 4000

P₂ = 6000 atm

Therefore, the new pressure, P₂ is 6000 atm.

Learn more about Boyle's law here:

brainly.com/question/23715689

#SPJ4

8 0

2 years ago

Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho

saveliy_v [14]

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

Half-life (t½) = 5730 years
Original amount (N₀) = 2.5×10¹⁵ g
Number of half-lives (n) = 5
Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

3 0

2 years ago

What is the frequency of radiation whose wavelength is 0.73 nm?

Travka [436]

405 PHz
I might be wrong because that might be for 0.74 nm. We will see with out people answers

8 0

3 years ago