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2 years ago

Balance all the equations

Chemistry

1 answer:

siniylev [52]2 years ago

5 0

Answer:

Balancing Chemical Equations

Balance the equations below:

1) __1__ N2 + __3__ H2 > _2__ NH3

2) __2__ KClO3 >⮴ __2__ KCl + __3__ O2

3) __2__ NaCl + __1__ F2 ⮴ __2__ NaF + __1__ Cl2

4) __2__ H2 + __1__ O2 ⮴ __2__ H2O

5) __1__ Pb(OH)2 + __2__ HCl ⮴ __2__ H2O + __1__ PbCl2

6)__2__ AlBr3 + __3__ K2SO4 ⮴ __6__ KBr + __1__ Al2(SO4)3

7) __1__ CH4 + __2__ O2 ⮴ __1__ CO2 + __2__ H2O

8) _1___ C3H8 + _5___ O2 ⮴ __3__ CO2 + __4__ H2O

9) __2__ C8H18 + __25__ O2 ⮴ __16__ CO2 + __18__ H2O

10) __1__ FeCl3 + __3__ NaOH ⮴ __1__ Fe(OH)3 + __3__NaCl

11) __4__ P + __5__O2 ⮴ __2__P2O5

12) __2__ Na + __2__ H2O ⮴ __2__ NaOH + __1__H2

13) __2__ Ag2O ⮴ __4__ Ag + __1__O2

14) __1__ S8 + __12__O2 ⮴ __8__ SO3

15) _6___ CO2 + _6___ H2O ⮴ __1__ C6H12O6 + __6__O2

16) ___1_ K + __1__ MgBr ⮴ __1__ KBr + __1__ Mg

17) __2__ HCl + __1__ CaCO3 ⮴ __1__ CaCl2 + __1__H2O + __1__ CO2

18) __1__ HNO3 + __1__ NaHCO3 ⮴ __1__ NaNO3 + __1__ H2O + _1___ CO2

19) _2___ H2O + __1__ O2 ⮴ __2__ H2O2

20) __2__ NaBr + __1__ CaF2 ⮴ __2__ NaF + __1__ CaBr2

Explanation:

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emmainna [20.7K]

I would personally convert the 12 mg to g so I could see what I was working with. So 12 mg to grams is 0.012 g...

so 1 tablet is 0.012g. the patient needs 0.024 g.

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3 years ago

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Vitamin C contains only carbon, hydrogen, and oxygen. When a 1.00 g was combusted, 1.4991 g of CO2 and 0.4092 g of H2O were obta

Alina [70]

The empirical formula for this vitamin : C₃H₄O₃

<h3>Further explanation </h3>

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

Determine the mass ratio of the constituent elements of the compound.
Determine the mole ratio by dividing the percentage by the atomic mass

Mass of C in CO₂ :(MW C = 12 g/mol, CO₂=44 g/mol)

$\tt \dfrac{12}{44}\times 1.4991=0.409~g$

Mass of H in H₂O :(MW H = 1 g/mol, H₂O = 18 g/mol)

$\tt \dfrac{2.1}{18}\times 0.4092=0.0455~g$

Mass O = Mass sample - (mass C + mass H) :

$\tt 1-(0.409+0.0455)=0.5455~g$

mol ratio C : H : O =

$\tt \dfrac{0.409}{12}\div \dfrac{0.0455}{1}\div \dfrac{0.5455}{16}\\\\0.0341\div 0.0455\div 0.0341\rightarrow 1\div 1.33\div 1=3\div 4\div 3$

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3 years ago

2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the eleme

mixer [17]

Answer:

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

$2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O$

Next, we assign the oxidation numbers as follows:

$2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}$

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

Regards!

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