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3 years ago

Balance all the equations

Chemistry

1 answer:

siniylev [52]3 years ago

5 0

Answer:

Balancing Chemical Equations

Balance the equations below:

1) __1__ N2 + __3__ H2 > _2__ NH3

2) __2__ KClO3 >⮴ __2__ KCl + __3__ O2

3) __2__ NaCl + __1__ F2 ⮴ __2__ NaF + __1__ Cl2

4) __2__ H2 + __1__ O2 ⮴ __2__ H2O

5) __1__ Pb(OH)2 + __2__ HCl ⮴ __2__ H2O + __1__ PbCl2

6)__2__ AlBr3 + __3__ K2SO4 ⮴ __6__ KBr + __1__ Al2(SO4)3

7) __1__ CH4 + __2__ O2 ⮴ __1__ CO2 + __2__ H2O

8) _1___ C3H8 + _5___ O2 ⮴ __3__ CO2 + __4__ H2O

9) __2__ C8H18 + __25__ O2 ⮴ __16__ CO2 + __18__ H2O

10) __1__ FeCl3 + __3__ NaOH ⮴ __1__ Fe(OH)3 + __3__NaCl

11) __4__ P + __5__O2 ⮴ __2__P2O5

12) __2__ Na + __2__ H2O ⮴ __2__ NaOH + __1__H2

13) __2__ Ag2O ⮴ __4__ Ag + __1__O2

14) __1__ S8 + __12__O2 ⮴ __8__ SO3

15) _6___ CO2 + _6___ H2O ⮴ __1__ C6H12O6 + __6__O2

16) ___1_ K + __1__ MgBr ⮴ __1__ KBr + __1__ Mg

17) __2__ HCl + __1__ CaCO3 ⮴ __1__ CaCl2 + __1__H2O + __1__ CO2

18) __1__ HNO3 + __1__ NaHCO3 ⮴ __1__ NaNO3 + __1__ H2O + _1___ CO2

19) _2___ H2O + __1__ O2 ⮴ __2__ H2O2

20) __2__ NaBr + __1__ CaF2 ⮴ __2__ NaF + __1__ CaBr2

Explanation:

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densk [106]

They are all correct good job bud I hope it helps and good luck

4 0

3 years ago

Read 2 more answers

If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

$\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g$

8 0

3 years ago

Write the balanced chemical Equation for the following when they are heated

ale4655 [162]

Answer:

i. Lead nitrate:

2Pb (NO3)2 Δ= 2PbO+4NO2+O2

ii. Potassium chlorate:

2KClO3 → 2KCl + 3O2↑

iii. clacium carbonate:

CaCO3 + 2HCl -> CaCl2 + CO2 + H2O

iv. cupric carbonate :

CuCO3 → CuO + CO2↑

Hope this helped

All the best!!

4 0

3 years ago

How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?

Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

$Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}$

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

$\frac{3}{2} \times 5.3 mol\\= 7.95 mol$

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

$No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g$

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

8 0

3 years ago

1. A 5.05 g sample of quartz (SiO2) contains 2.36 g of silicon. What are the percentages of silicon

hammer [34]

Answer: B) 46.7% Si and 53.3% O

Explanation:

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{total mass}}\times 100\%$

Mass of quartz $(SiO_2)$ = 5.05 g

Mass of silicon = 2.36 g

Mass of oxygen = Mass of quartz $(SiO_2)$ - mass of silicon = 5.05g - 2.36 g = 2.69 g

$\text{Mass percent of silicon}=\frac{\text{Mass of silicon}}{\text{total mass of quartz}}\times 100=\frac{2.36}{5.05}\times 100=46.7\%$

$\text{Mass percent of oxygen}=\frac{\text{Mass of oxygen}}{\text{total mass of quartz}}\times 100=\frac{2.69}{5.05}\times 100=53.3\%$

Thus the percentages of silicon and oxygen in quartz are B) 46.7% Si and 53.3% O

6 0

3 years ago