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Strike441 [17]
3 years ago
11

Why is it wrong to leave our light on​

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

you will get huge electricity bills ............

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If the distance between two asteroids is halved, the gravitational force they exert on each other will
mamaluj [8]

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_{1} & m_{2}) and the distance between them (r) in the next way:

F=G\frac{m_{1}m_{2}}{r^{2}} (2)

Now if distance between asteroids is halved:

F_{2}=G\frac{m_{1}m_{2}}{(\frac{r}{2})^{2}}

F_{2}=G\frac{m_{1}m_{2}}{\frac{r^{2}}{4}}

F_{2}=G\frac{4m_{1}m_{2}}{r^{2}}=4G\frac{m_{1}m_{2}}{r^{2}}

Note that G\frac{m_{1}m_{2}}{r^{2}} because (1) is F so:

F_{2}=4F

It's four times greater!

3 0
3 years ago
True or false as heat and pressure decreases one type of metamorphic rock will transform into another type
dezoksy [38]

Answer: True

Explanation:  Metamorphism is the changing of rocks by heat and pressure. During this process, rocks change either physically and/or chemically. They change so much that they become an entirely new rock. Figure 4.22: The platy layers in this large outcrop of metamorphic rock show the effects of pressure on rocks during metamorphism.

6 0
3 years ago
Give 3 combinational logic circuits on basic electronic devices that can be found at home.
Umnica [9.8K]

Answer:

Leds switchs battery

Explanation:

....................

4 0
3 years ago
Read 2 more answers
4. A motorist travels 406 km during a 9.0 hr period. What was the average speed in km/hr and m/s?
user100 [1]

Answer:

45.11 kmph and 12.530 m/s

Explanation:

Average speed = Total distance travelled / Total time taken

406/9 gives the answer in kilometers

And we convert it to m/s by multiplying it with 1000/3600

6 0
3 years ago
Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molec
Vlad1618 [11]

Complete Question

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as N=1/\lambda\  cm^{-1})

Answer:

The ratio of intensities is  I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

Explanation:

 From the question we are told that

        The number of sets of satellite is n = 4

        The temperature is  T = 27 ^oC

        The resonant infrared frequencies are f_1 = 217 cm^{-1}

                                                                          f_2 = 315 cm^{-1}

                                                                          f_3 = 457 cm^{-1}

                                                                          f_4 = 774 cm^{-1}

From the question we see that the wave number also has a unit ofcm^{-1} hence  the value of the wave numbers of the molecule are

                                                                            N_1 = 217 cm^{-1}                

                                                                          N_2 = 315 cm^{-1}

                                                                          N_3 = 457 cm^{-1}

                                                                          N_4 = 774 cm^{-1}

Generally intensity is mathematically represented as

             I = \frac{nhc}{A \lambda }

Here we see that  I varies inversely with wavelength  i,.e

         I \ \ \alpha \ \ \frac{1}{\lambda }              

From the question we are told that the wave number is mathematically represented as

         N  = \frac{1}{\lambda }

Therefore

          I \ \ \alpha \ \  N

This implies that  the ratio of intensity in first set to that of second set to that of third set to that of fourth set is  equal to the ratio of the wavenumber in the first set to that of the second set  to that of third set to that of fourth

     This is mathematically represented as

               I_1 : I_2 : I_3 : I_4 = N_1 : N_2 : N_3 : N_4

Substituting values

        I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

                     

5 0
4 years ago
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