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Alex Ar [27]
3 years ago
11

Explain what happens when a massive star ends its life as a supernova

Physics
1 answer:
Bingel [31]3 years ago
6 0
The ultimate fate of a star depends on its mass.
A massive star ends with a violent explosion called a supernova.
The matter ejected in a supernova explosion becomes a glowing supernova remnant.

Toward the end of its life, a massive supergiant star has a central iron core, surrounded by a shell where silicon is being fused to iron, surrounded by a shell where oxygen is being fused, surrounded by a shell where carbon is being fused, surrounded by a shell where helium is being fused, surrounded by a shell where hydrogen is being fused.

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Read 2 more answers
(a) Calculate the force needed to bring a 950-kg car to rest from a speed of 90.0 km/h in a distance of 120 m (a fairly typical
musickatia [10]

(a)

mass of the car: m=950 kg

Initial speed: u = 90.0 km/h=25 m/s

Final speed: v=0 (the car comes to rest)

distance: S=120 m

We can find the acceleration by using the following SUVAT equation:

v^2 -u^2 =2aS

Re-arranging it and replacing the numbers, we find the acceleration

a=\frac{v^2-u^2}{2S}=\frac{0-(25 m/s)^2}{2(120 m)}=-2.6 m/s^2

So now we can calculate the force using Newton's second law:

F=ma=(950 kg)(-2.6 m/s^2)=-2470 N

And the negative sign means the force is applied against the direction of motion.

(b)

In this case, the distance is different:

S=2.00 m

so, the acceleration in this case is

a=\frac{v^2-u^2}{2S}=\frac{0-(25 m/s)^2}{2(2 m)}=-156.3 m/s^2

And so, the force applied in this case is

F=ma=(950 kg)(-156.3 m/s^2)=-148 500 N

which is much larger than the force exerted in the previous exercise.


6 0
4 years ago
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