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kherson [118]
3 years ago
14

If 7 ocean waves pass a point in 4 minutes, then the frequency of the wave is:

Physics
1 answer:
kirza4 [7]3 years ago
6 0

Explanation:

everything can be found in the picture.

sorry I don't know why your answers to not correspond but my method is correct

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A car traveling at 23 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?
kykrilka [37]
We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers
a= \dfrac{v_{1}-v_{0}}{t}
a= \dfrac{0-23}{5}
a= \dfrac{-23}{5}
a = -4.6
The acceleration is -4.6 m/s²
8 0
3 years ago
For a spacecraft or a molecule to leave the moon, it must reach the escape velocity (speed) of the moon, which is 2.37 km/s. The
guapka [62]

Answer:

Vrms = 291 m/s

Explanation:

The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.

Temperature = 365 K

Root mean square velocity = ?

molar mass of oxygen = 16 g/mol.

But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:

   molar mass of O2 = 2 x 16

   molar mass of O2 = 32 g/mol

   Convert this to kg/mol:

   molar mass of O2 = 32 g/mol x 1 kg/1000 g

   molar mass of O2 = 3.2 x 10-2 kg/mol

Molar mass of Oxygen = 3.2 x 10-2 kg/mol

Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]

Vrms = 291 m/s

8 0
4 years ago
Read 2 more answers
Say you dropped a cannonball from the 17.0–meter mast of a ship sailing at 2.0 meters/second. How far from the base of the mast
Mice21 [21]

The correct choice is A. 0 meters.

If you simply dropped the cannonball and didn't throw it horizontally,

then it'll fall straight down the mast and land on the deck right next to

the mast.


While you were up there holding it, before you dropped it, the cannonball

was moving horizontally, at 2.0 meters/second, along with the rest of the

ship and everything else aboard. It continued doing that after it dropped,

and from the point of view (in the reference frame) of the mast and everyone

on the ship, it fell straight down, parallel to the mast.


Now that we have that question answered, we can proceed to the more-

important ones. I answered the easy one, but YOU'll have to answer these:


==> WHY did you climb the mast carrying a cannonball ?

Have you been drinking sea water or bad rum ?


==> WHY did you drop it, and never even yell "LOOK OUT BELOW !" ?


==> How many formerly-able-bodied souls were injured by the

plummeting cannonball ?


==> What did everybody ELSE yell after the impact ?


==> What did they do to you after they brought you down ?

3 0
3 years ago
Read 2 more answers
5) A person holds a 1.7 kg bucket and lets it move down at
Elena L [17]

Answer:

12.5J

Explanation:

Given parameters:

Mass of bucket  = 1.7kg

Height  = 75cm  = 0.75m

Unknown;

Work done on the bucket by the person  = ?

Solution:

To solve this problem, we use the work done equation;

  Work done  = force x distance  = mgh

 m is the mass  

  g is the acceleration due to gravity

  h is the height

Now, insert parameters and solve ;

     Work done  = 1.7 x 9.8 x 0.75  = 12.5J

7 0
3 years ago
When reading the printout from a laser printer, you are actually looking at an array of tiny dots.
solniwko [45]

Answer:

The value is y  = 3.097 * 10^{-5} \  m

Explanation:

From the question we are told that

The diameter of the pupil is d_p  =  4.2 \ mm  =  4.2 *10^{-3} \  m

The distance of the page from the eye d =  29 \  cm  =  0.29 \  m

The wavelength is \lambda  =  500 \ nm =  500 *10^{-9} \  m

The refractive index is n_r =  1.36

Generally the minimum separation of adjacent dots that can be resolved is mathematically represented as

y  = [ \frac{1.22 *  \lambda }{d_p * n_r } ]* d

         y  = [ \frac{1.22 *  500 *10^{-9} }{4.2 *10^{-3} * 1.36} ]* 0.29

         y  = 3.097 * 10^{-5} \  m

7 0
3 years ago
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