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3 years ago

¿Cuál es la aceleración de un auto que se mueve con MRUV si en un

Physics

2 answers:

V125BC [204]3 years ago

6 0

Answer:

your answer is different than mine

nika2105 [10]3 years ago

6 0

Answer:

Datos: Formula:

M: 22 m/s F: M x V

V: 36 km/hr F: 22 m/s x 36 km/hr

F: ¿? F: 792 km o N

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Why does sugar sink to the bottom of the teacup (for science btw)

TEA [102]

I know what you are wondering and the answer is simply crystals are more dense than water , so they sink but if you warm it up they can combine with it to become one.
dose this help?

3 0

3 years ago

A team of bicyclists are on bikes that require 512 J of work to ride. It takes 432 J of work for the bike to turn the gears. Wha

Alja [10]

Answer:

84.4 %

Explanation:

Mechanical efficiency = output work/input work × 100 %

output work = 432 J of work for the bike to turn the gears

input work = 512 J of work to ride.

Mechanical efficiency = 432 J/512 J × 100 %

= 0.844 × 100%

= 84.4 %

8 0

3 years ago

A brass alloy is known to have a yield strength of 240 MPa (35,000 psi), a tensile strength of 310 MPa (45,000 psi), and an elas

Karo-lina-s [1.5K]

Answer:

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

Explanation:

Given that

Yield strength ,Sy= 240 MPa

Tensile strength = 310 MPa

Elastic modulus ,E= 110 GPa

L=380 mm

ΔL = 1.9 mm

Lets find strain:

Case 1 :

Strain due to elongation (testing)

ε = ΔL/L

ε = 1.9/380

ε = 0.005

Case 2 :

Strain due to yielding

$\varepsilon' =\dfrac{S_y}{E}$

$\varepsilon' =\dfrac{240}{110\times 1000}$

ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

For computation of load strain due to testing should be less than the strain due to yielding.

4 0

3 years ago

A leaky faucet drips once each second. at this rate, it takes 1 hour to fill a 1-liter graduated cylinder to the 200-cm3 mark. w

UNO [17]

Define
v = volume of a drop per second, cm³/s

The time taken to fill 200 cm³ is 1 hour.
Let V = 200 cm³, the filled volume.
Let t = 1 h = 3600 s, the time required to fill the volume.

Therefore,
$\frac{200 \, cm^{3}}{v \, cm^{3}/s} = 3600 \, s \\ v = \frac{200}{3600} =0.0556 \, cm^{3}$

The average volume of a single drop is approximately 0.0556 cm³.

Answer: 0.0556 cm³

8 0

3 years ago

Below is an oscilloscope trace from an AC supply. Calculate the frequency of the supply if each horizontal division represents 0

GuDViN [60]

Answer:

20 hertz of frequency produced.

Explanation:

$\boxed{frequency = \frac{1}{period} }$