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3 years ago

You need 65.0 g of aluminum for an experiment. How many atoms of aluminum is that?

Chemistry

1 answer:

nikdorinn [45]3 years ago

5 0

Answer:

Explanation:

To convert the mass of Aluminum to atoms, we must first convert to moles by using the formula;

mole = mass/molar mass

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How many grams S03 are needed to make 400g H₂So4 in 49%

NemiM [27]

160 g of SO3 are needed to make 400 g of 49% H2SO4.

<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

$SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}$

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

Learn more about mass and moles at: brainly.com/question/15374113

#SPJ1

7 0

2 years ago

Suppose now that you wanted to determine the density of a small crystal to confirm that it is boron. From the literature, you kn

Phantasy [73]

Answer:

the volume of CHCI3 = 7.87 ml

the volume of CHBr3 = 12.13 ml

Explanation:

From the given information:

We all know that 1 g/cm^3 = 1 g/ml

The density of boron = 2.34 g/ml

The Volume of the liquid mixture = 20 ml

Recall that:

Density = mass/volume

Mass = Density × Volume

Mass = 2.34 g/ml × 20 ml

Mass = 46.8 g

Suppose the volume of CHCI3 be Y and the Volume of CHBr3 be 20 - Y

Then :

Y (1.492) + 20-Y(2.890) = 46.8

1.492Y + 57.8 - 2.890Y = 46.8

- 1.398 Y = -11

Y = -11/ - 1.398

Y = 7.87 ml

Therefore, the volume of CHCI3 7.87 ml

the volume of CHBr3 = 20 - Y

= 20 - 7.87

= 12.13 ml

3 0

3 years ago

HElp me plzzzzz??????

iris [78.8K]

Answer:

The answer to your question is given below

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl2 + H2

Thus, we can write out the atoms present in both the reactant and the product by doing a simple head count. The atoms present are listed below:

Element >>> Reactant >>> Product

Zn >>>>>>>> 1 >>>>>>>>>> 1

H >>>>>>>>> 2 >>>>>>>>> 2

Cl >>>>>>>>> 2 >>>>>>>>> 2

4 0

3 years ago

A soft drink contains 12.1% sucrose (C12H22O11) by mass. What volume of the soft drink solution in milliliters contains 102.5 g

galina1969 [7]

The volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

<h3>How to calculate volume?</h3>

The volume of a solution can be calculated by dividing the mass by the density. That is;

Volume = mass/density

According to this question, a soft drink contains 12.1% sucrose (C12H22O11) by mass. This means that the mass of the sucrose is

12.1/100 × 102.5 = 12.40g of sucrose

Volume = 12.40g ÷ 1.04g/mL

Volume = 11.93mL

Therefore, the volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

Learn more about volume at: brainly.com/question/1578538

4 0

2 years ago

Substance P is carbon.

stepan [7]

Explanation:

substance Q could be oxygen (O2)

substance R could be carbon dioxide (CO2)

4 0

3 years ago