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laiz [17]
2 years ago
14

2-ethyl-4,4-dimethyl-2-octanone. Draw the structure

Chemistry
1 answer:
Dvinal [7]2 years ago
5 0
Is there a picture maybe? I can’t help you
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Calculate the energy required to melt 21 g of ice at 0 oC.
vladimir1956 [14]

<u>We are given:</u>

Mass of ice = 21 grams

The ice is already at 0°c, the temperature at which it melts to form water

Molar heat of fusion of Ice = 6.02 kJ/mol

<u>Finding the energy required:</u>

<u>Number of moles of Ice: </u>

Molar mass of water = 18 g/mol

Number of moles = given mass/ molar mass

Number of moles = 21 / 18 = 7/6 moles

<u>Energy required to melt the given amount of ice:</u>

Energy = number of moles * molar heat of fusion

Energy = (7/6) * (6.02)

Energy = 7.02 kJ OR 7020 joules

7 0
3 years ago
In the compound CO2, how many lone pairs are on the central atom?
Cloud [144]
There are 4 lone pairs of electrons present in the carbon dioxide molecule 
4 0
3 years ago
As a chemical reaction occurs, the thermometer in the container records a drop in temperature. What is true of the reaction?
nadya68 [22]
<span>When a chemical reaction occurs and the thermometer in the container records a drop in temperature t</span>he reaction is exothermic because heat was released by the reaction.

 <span>B. The reaction is exothermic because heat was released by the reaction. is your answer.

Hoped I helped!</span>
4 0
3 years ago
Read 2 more answers
When you light a fireplace what energy transformation occurs?
snow_tiger [21]
<span>thermal energy

hope this helped</span>
4 0
3 years ago
Fluorine-21 has a half life of approximately 5 seconds. You have 340 grams, what fraction of the original nuclei would remain af
madreJ [45]
The half life equation is -->P(t) = Pi (0.5) ^ (t/c)
c is equal to the element to reach its half-life (5 seconds)t is equal to the duration of time the element is expose to (20 seconds)Pi is the initial amount (340)0.5 is the base of this exponential function to represent half-life.P(t) is the expression for the function of time

P(20) = 340 (0.5)^20/5P(20) = 340 (0.5) ^4P(20)= 21.25 grams
Fraction = P(t)/Pi              = P(20)/Pi              =21.25/340              =1/16
Therefore, when given 20 seconds, 340 grams of Fluorine-21 will degrade to 21.25 grams OR 1/16 of its original mass.
Hope this method helps! (This is my answer btw, I think you may have accidentally posted twice?)
7 0
3 years ago
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