Question

An ideal gas has a temperature of 25 oC, a pressure of 1.7 atm, and volume of 345 mL, how many moles of gas are present in the container?

Answer 1

Answer: There are 0.024 moles of gas are present in the container.

Explanation:

Given: Temperature = $25^{o}C$ = (25 + 273) K = 298 K

Pressure = 1.7 atm

Volume = 345 mL (1 mL = 0.001 L) = 0.345 L

Formula used is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T= temperature

Substitute the values into above formula as follows.

$PV = nRT\\1.7 atm \times 0.345 L = n \times 0.0821 L atm/mol K \times 298 K\\n = \frac{1.7 atm \times 0.345 L}{0.0821 L atm/mol K \times 298 K}\\= \frac{0.5865}{24.4658} mol\\= 0.024 mol$

Thus, we can conclude that there are 0.024 moles of gas are present in the container.