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RSB [31]
4 years ago
11

If the mean velocity adjacent to the top of a wing of 1.8 m chord is 40 m/s and that adjacent to the bottom of the wing is 31 m/

s when the wing moves through still air at 33.5 m/s, estimate the lift per meter of span.

Physics
1 answer:
Cloud [144]4 years ago
7 0

Answer:

lift per meter of span = 702 N/m

Explanation:

See attached pictures.

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STUDY QUESTIONS
tankabanditka [31]

Answer:

The blade of sharpener is made up of iron. Iron is a magnetic material because of this pencil sharpener gets attracted by the poles of a magnet although the body is made up of plastic.

5 0
3 years ago
What kind of circuit is the one shown below?
lions [1.4K]

Answer:

The given circuit diagram shows parallel circuit.

Explanation:

In this circuit diagram two bulbs are connected in parallel combination because current flows from the battery gets bifurcated at the junction. Thus, two bulbs are connected in parallel combination.

This parallel combinations of bulbs then connected to the battery given in the diagram. So, the combinations of bulbs are connected in parallel combinations with the battery.

Hence, both bulbs and battery are connected in parallel combinations with each other.

The circuit diagram shown in figure is parallel.


8 0
3 years ago
Read 2 more answers
Please help !!!!!!!!!!!!’
Zanzabum

Answer:

GYU

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6 0
3 years ago
An isolated conducting sphere has a 10 cm radius. One wire carries a current of 1.000 002 0 A into it. Another wire carries a cu
romanna [79]

Answer:

t = 5.56 ms

Explanation:

Given:-

- The current carried in, Iin = 1.000002 C

- The current carried out, Iout = 1.00000 C

- The radius of sphere, r = 10 cm

Find:-

How long would it take for the sphere to increase in potential by 1000 V?

Solution:-

- The net charge held by the isolated conducting sphere after (t) seconds would be:

                                   qnet = (Iin - Iout)*t

                                   qnet = t*(1.000002 - 1.00000) = 0.000002*t

- The Volt potential on the surface of the conducting sphere according to Coulomb's Law derived result is given by:

                                   V = k*qnet / r

Where,                        k = 8.99*10^9   ..... Coulomb's constant

                                   qnet = V*r / k

                                   t = 1000*0.1 / (8.99*10^9 * 0.000002)

                                   t = 5.56 ms

                                   

7 0
3 years ago
Stars fuse most of the hydrogen in the entire star before they die.<br> 2 poir<br> True<br> False
Margaret [11]
Once all hydrogen is depleted the star begins to die
3 0
3 years ago
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