If the mean velocity adjacent to the top of a wing of 1.8 m chord is 40 m/s and that adjacent to the bottom of the wing is 31 m/
s when the wing moves through still air at 33.5 m/s, estimate the lift per meter of span.
1 answer:
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Answer:
E= 55.53 x 10³ V/m
Explanation:
Given that
a= 3.63 cm
Area ,A= a²
distance ,d= 0.473 mm
Stored energy ,U = 8.49 nJ
Value of capacitor given as
By putting the values
C=2.46 x 10⁻¹¹ F
V=Voltage difference
V=26.27 V
V= E d
E=Electric filed
26.27 = E x 0.473 x 10⁻³
E= 55.53 x 10³ V/m