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kozerog [31]
3 years ago
5

Laney left a nail in water for two weeks, and the nail became rusted from sitting in the water.

Chemistry
1 answer:
Simora [160]3 years ago
5 0
B) A chemical change because the nail reacts with water/oxygen to create rust (a type of oxide)
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Developing countries use many more resources than do developed countries. True False
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Glucose and fructose are monosaccharides that have the same chemical formula, C6H12O6. However, they do not react the same chemi
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Monosaccharides are the simplest carbohydrates. Although glucose and fructose have the same molecular formula they have different structures or the atoms are arranged differently from each other and this is evident in the way they react, behave and in their properties. 
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Carvone (C10H14O) is the main component of spearmint oil. It has a pleasant aroma and mint flavor. Carvone is often added to che
marta [7]

<u>Answer:</u> The mass of carbon in given amount of carvone is 47.52 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carvone = 55.4 g

Molar mass of carvone = 150.22 g/mol

Putting values in equation 1, we get:

\text{Moles of carvone}=\frac{55.4g}{150.22g/mol}=0.369mol

The chemical formula of carvone is C_{10}H_{14}O

This contains 10 moles of carbon atom, 14 moles of hydrogen atom and 1 mole  of oxygen atom

Now, calculating the mass of carbon in carvone from equation 1, we get:

Molar mass of carbon = 12 g/mol

Moles of carbon = (10 × 0.396) = 3.96 moles

Putting values in equation 1, we get:

3.96mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=(3.96mol\times 12g/mol)=47.52g

Hence, the mass of carbon in given amount of carvone is 47.52 grams

6 0
3 years ago
You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

3 0
3 years ago
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