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Answer:
W = - 184.8 kW
Explanation:
Given data:





We know that work is done as
![W = - [ Q + \dor m[h_2 - h_1]]](https://tex.z-dn.net/?f=W%20%3D%20-%20%5B%20Q%20%2B%20%5Cdor%20m%5Bh_2%20-%20h_1%5D%5D)
for
density of air is 1.22 kg/m^3 and 
for 


W = -[14 + 1.708[400-300]]
W = - 184.8 kW
Answer:
What is percentage modulation in AM?
The percent modulation is defined as the ratio of the actual frequency deviation produced by the modulating signal to the maximum allowable frequency deviation.
A continuous time-varying 1-D signal is sampled by narrow sampling pulses at a regular rate fr = 1/T, which must be at least twice the bandwidth of the signal. At first, it may be somewhat surprising that the original waveform can be reconstructed exactly from a set of discrete samples.