Conclusion is the answer you are looking for
The balanced chemical reaction is given as:
<span>2H2S (g) + 3O2 (g) 2SO2 (g) + 2H2O (g)
We are given the volume at STP of H2S to be used for the reaction. This would be the starting point for the calculations. We do as follows:
45.0 L H2S ( 1 mol / 22.4 L) ( 3 mol O2 / 2 mol H2S ) ( 22.4 L / 1 mol ) = 67.5 L O2 needed </span>
We are not able to know that the galaxy have oval or sperical shape because we have not such modern technology to look over it
Answer:I believe it is c.
Explanation:
Answer:
The equilibrium constant of the reaction is
.
Explanation:
Formula used:


where :
= Gibbs free energy
= Enthalpy of reaction
= Entropy of reaction
R = Gas constant = 
T = Temperature in Kelvins
= equilibrium constant at T
So we have:
= ?
= -94.9 kJ/mol = -94900 J/mol
= -224.2 J/mol K
T = 549 K




The equilibrium constant of the reaction is
.