Answer:
5437.5 N
Explanation:
from the question we are given the following:
mass = 7.25 kg
initial speed (u) = 10.5 
finial velocity (v) = 0
compression (s) = -7.35 cm = -0.0735 m (the negative sign is because the face is compressed, so there is a decrease)
we know that force = mass x acceleration,
we have our mass but need to find the acceleration. we can get the acceleration by applying the formula below
therefore
0 = 10.5^{2} + (-2)× a × 0.0735[/tex]
a = 
}[/tex]
a = 750
from F = m x a
force = 7.25 x 750 = 5437.5 N
Answer:
HII CAN I HAVE BRAINLIST PLEASE I NEED ONE MORE
Explanation:
Answer:
2. Galaxy
5. Electromagnetic radiation
7. Particle Accelerator
The formula is F = ( q1 * q2 ) / r ^ 2
<span>where: q is the individual charges of each ion </span>
<span>r is the distance between the nuclei </span>
<span>The formula is not important but to explain the relationship between the atoms in the compounds and their lattice energy. </span>
<span>From the formula we can first conclude that compounds of ions with greater charges will have a greater lattice energy. This is a direct relationship. </span>
<span>For example, the compounds BaO and SrO, whose ions' charges are ( + 2 ) and ( - 2 ) respectively for each, will have greater lattice energies that the compounds NaF and KCl, whose ions' charges are ( + 1 ) and ( - 1 ) respectively for each. </span>
<span>So Far: ( BaO and SrO ) > ( NaF and KCl ) </span>
<span>The second part required you find the relative distance between the atoms of the compounds. Really, the lattice energy is stronger with smaller atoms, an indirect relationship. </span>
<span>For example, in NaF the ions are smaller than the ions in KCl so it has a greater lattice energy. Because Sr is smaller than Ba, SrO has a greater lattice energy than BaO. </span>
<span>Therefore: </span>
<span>Answer: SrO > BaO > NaF > KCl </span>
The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by
where f1 is the fundamental frequency.
In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
so their difference is
So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
