The correct answer is "<span>stormy weather".
In fact, barometric low pressure is generally associated with rain, precipitations, or more in general with bad weather. On the contrary, high atmospheric pressure is usually associated with sunny weather.</span>
Answer:
M = 0.730*m
V = 0.663*v
Explanation:
Data Given:

Conservation of Momentum:

Energy Balance:

Substitute Eq 2 into Eq 1

Using Eq 1

The right half will be a new bar magnet of 2cm with north pole on the right side and south pole on teh left.
4000 grams kilo means thousand
Alot as far as i know unless you need it in formal terms.