Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
![Y = \dfrac{[L]}{k_d+[L]}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7Bk_d%2B%5BL%5D%7D)
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
![0.25 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.25%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
![0.6 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
![0.95 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.95%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
Because C-12 is fixed value of any organisms but the value of C-14 is constantly decreasing by time thats why every organism have their specific ratio of C14/C12
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
It is a covalant bond. Because any compound made up of nonmetals will be covalant. Compounds made up of a non metal and metal willl form a ionic compund. :)
