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zysi [14]
3 years ago
10

Which group of human life cycle stages is in the correct order

Chemistry
1 answer:
zysi [14]3 years ago
8 0

Answer:

foetus, baby, child, adolescent, adult and old person

Explanation:

eeet eez wut eeet eez

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A binding protein binds to a ligand L with a Kd of 400 nM. What is the concentration of ligand when Y is (a) 0.25, (b) 0.6, (c)
Mrac [35]

Answer:

(a) 133.33nm

(b) 600nm

(c) 7,600nm

Explanation:

The concentration of Y can be determined by using the formula:

Y = \dfrac{[L]}{k_d+[L]}

where;

[L] = concentration of the binding ligand.

kd = 400 nm

Thus:

When Y = 0.25; we get :

0.25 = \dfrac{[L]}{400+[L]}

0.25 (400 + [L]) = [L]

100 + 0.25[L] = [L]

100 = [L] - 0.25 [L]

100 = 0.75 [L]

[L] = 100/0.75

[L] = 133.33 nm

At, Y = 0.6

0.6 = \dfrac{[L]}{400+[L]}

0.6 (400 + [L]) = [L]

240 + 0.6[L] = [L]

240 = [L] - 0.6 [L]

240 = 0.4 [L]

[L] = 240/0.4

[L] = 600 nm

At, Y = 0.95

0.95 = \dfrac{[L]}{400+[L]}

0.95 (400 + [L]) = [L]

380 + 0.95[L] = [L]

380 = [L] - 0.95 [L]

380 = 0.05 [L]

[L] = 380/0.05

[L] = 7600 nm

4 0
3 years ago
Why is the C-14/C-12 ratio used to date once-living organisms?
ki77a [65]
Because C-12 is fixed value of any organisms but the value of C-14 is constantly decreasing by time thats why every organism have their specific ratio of C14/C12
8 0
3 years ago
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The second step is to calcul
Free_Kalibri [48]
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.

2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O

1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

Empirical formula
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Hands moving on a battery-operated clock is an example of what kind of
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The C is right answer
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Is carbon dioxide a iconic or covalent compound
igomit [66]
It is a covalant bond. Because any compound made up of nonmetals will be covalant. Compounds made up of a non metal and metal willl form a ionic compund. :)
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