3 years ago

URGENT HELP! VIEW PICTUItE 10 POINTS IF U GET I RIGHT

Mathematics

1 answer:

Tamiku [17]3 years ago

5 0

The answer would be 3•n/5 which would be c

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Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle

mario62 [17]

Step-by-step explanation:

The distance formula between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points.

$A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}$

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

$\sqrt5$

used $(\sqrt{a})^2=a$ for a ≥ 0.

$AB^2+BC^2=AC^2$ therefore ΔABC is a right triangle.

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Mona, Tabitha, and Reid are at a frozen yogurt shop. At the shop, frozen yogurt and toppings are charged by the ounce. The follo

tatiyna

Answer:

A.$0.45

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3 years ago

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Point P is located at (–3, –2). P is reflected across the x-axis to create P'. What quadrant is P' in?

Eva8 [605]

Look at the axis graph. If both of the coordinates are negative, it would be in quadrant lll. If you go over to the x-axis, you would be in quadrant lV, or 4.

(-2,-3) -> (2,-3)

You change the x-factor's sign.

I hope this helps!
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3 years ago

Complete the table and draw the graph

Neko [114]

Answer:

So the vaule of y is 7, 10 & 13

Step-by-step explanation:

Given that y = 3x+1 . So we can just substitute x-value into the equation :

Let x=2,

y = 3(2)+1

= 7

Let x=3,

y = 3(3)+1

= 10

Let x=4,

y = 3(4)+1

= 13

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3 years ago

X+20≥-7 i need help pls lollllllllllllllllllllllllll

Zina [86]

Answer:

Step-by-step explanation:

x is greater or equal to 13

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3 years ago

URGENT HELP! VIEW PICTUItE **10 POINTS** IF U GET I RIGHT​

URGENT HELP! VIEW PICTUItE 10 POINTS IF U GET I RIGHT