Answer:
25 m/s
Explanation:
Centripetal acceleration is the square of the tangential velocity divided by the radius.
a = v² / r
15.625 m/s² = v² / (40 m)
v² = 625 m²/s²
v = 25 m/s
The speed of the car is 25 m/s.
C I think lol but I have to keep typing
Answer:
Revolutions made before attaining angular velocity of 30 rad/s:
θ = 3.92 revolutions
Explanation:
Given that:
L(final) = 10.7 kgm²/s
L(initial) = 0
time = 8s
<h3>
Find Torque:</h3>
Torque is the rate of change of angular momentum:
<h3>Find Angular Acceleration:</h3>
We know that
T = Iα
α = T/I
where I = moment of inertia = 2.2kgm²
α = 1.34/2.2
α = 0.61 rad/s²
<h3>
Find Time 't'</h3>
We know that angular equation of motion is:
ω²(final) = ω²(initial) +2αθ
(30 rad/s)² = 0 + 2(0.61 rad/s²)θ
θ = (30 rad/s)²/ 2(0.61 rad/s²)
θ = 24.6 radians
Convert it into revolutions:
θ = 24.6/ 2π
θ = 3.92 revolutions
Answer:
<em>The officer would calculate the similar value of Edef.</em>
Explanation:
As Edef is the energy required to deform the body therefore the reference frame does not affect the calculation of energy. In this context the value of Edef will remain same irrespective of fact, whichever frame of reference is used.
<span>2) s(t) = 155tcos(23°) </span>
<span>=> s(1.4) = 155 * 1.4 * cos(23°) </span>
<span>=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally </span>
<span>a(t) = -32 ft/s^2 </span>
<span>=> v(t) = -32t + 155sin(23°) </span>
<span>=> h(t) = -16t^2 + 155tsin(23°) </span>
<span>=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°) </span>
<span>=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.</span>
