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3 years ago

11. A dog sits 2.50m from the center of a merry-go-round and revolves at a tangential

1 answer:

5 0

Fc=mv2/r formula of centripetal force will be applied here with radius mass and velocity described in the above question

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A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a

monitta

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3 years ago

The Apollo Lunar Module was used to make the transition from the spacecraft to the Moon's surface and back. Consider a similar m

ivolga24 [154]

Answer:

v=6.05 m/s

Explanation:

Given that,

Th initial velocity of the lander, u = 1.2 m/s

The lander is at a height of 1.8 m, d = 1.8 m

We need to find the velocity of the lander at impact. It is a concept based on the conservation of mechanical energy. So,

$\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=W\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=F\times d\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=mgd\\\\\dfrac{1}{2}m(v^2-u^2)=mgd\\\\v^2-u^2=2gd$

v is the velocity of the lander at the impact

g is the acceleration due to gravity on the surface of Mars, which is 0.4 times that on the surface of the Earth, g = 0.4 × 9.8 = 3.92 m/s²

So,

$v=\sqrt{u^2+2gd} \\\\v=\sqrt{(1.2)^2+2\times 9.8\times 1.8} \\\\v=6.05\ m/s$

So, the velocity of the lander at the impact is 6.05 m/s.

6 0

3 years ago

Which best describes longitudinal waves?

RUDIKE [14]

The right answer for the question that is being asked and shown above is that: "A. Compressions and rarefactions make up longitudinal waves, which can only travel in matter." The statement that best describes longitudinal waves is that c<span>ompressions and rarefactions make up longitudinal waves, which can only travel in matter.</span>

3 0

3 years ago

A uniform cylindrical grinding wheel of mass 50.0 kg and diameter 1.0 m is turned on by an electric motor. The friction in the b

aliya0001 [1]

Answer:

The torque must be applied to the wheel is 15.7 N-m.

Explanation:

Given that,

Mass of the wheel of cylinder, m = 50 kg

Diameter of the wheel, d = 1 m

Radius, r = 0.5 m

Initial speed off the wheel is 0

Final angular speed of the wheel, 120 rev/min = 12.56 rad/s

Angular displacement, $\theta=20\ rev=125.6\ rad$

The torque is given by :

$\tau=I\alpha \\\\\tau=\dfrac{mr^2}{2}\times (\dfrac{\omega_f^2}{2\theta})\\\\\tau=\dfrac{50\times1^{2}}{2}\times(\dfrac{12.56^{2}}{2\times125.6})\\\\\tau=15.7\ N-m$

So, the torque must be applied to the wheel is 15.7 N-m.

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3 years ago

If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the accel

Studentka2010 [4]

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

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3 years ago

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