Determine the mechanical energy of this object: a 1-kg pendulum has a speed of 2 m/s ar a height of 1 meter.

A second rock is thrown straight upward with a speed 4.750 m/s . If this rock takes 2.006 s to fall to the ground, from what hei

Naddika [18.5K]

Answer:

29.23 meters

Explanation:

H = ut + 1/2gt^2

Initial velocity u = 4.750m/s

time t = 2.006 secs

Acceleration due to gravity g = 9.8m/s^2

H =

4.750 x 2.006 + 1/2 x 9.8 x (2.006)^2

9.53 + 1/2 x 9.8 x 4.02

9.53 + 39.396/2

9.53 + 19.698

29.23 meters

8 0

3 years ago

in a paragraph explain how electncity is generated at a power plant. please don't answer if you don't know

Anna [14]

Answer:

A turbine spins to generate electricity. There are many ways to spin the turbine by using water, steam, nuclear and so on.

3 0

3 years ago

A ten loop coil of area 0.23 m2 is in a 0.047 T uniform magnetic field oriented so that the maximum flux goes through the coil.

Nana76 [90]

Answer:

0.32 V

Explanation:

N = 10, A = 0.23 m^2, B = 0.47 T, t = 0.34 s

The average induced emf is given by

e = - N dФ / dt

Where, dФ be the change in magnetic flux in time dt.

dФ / dt = d / dt (B A) = A dB/dt

So,

e = - 10 x 0.23 x 0.047 / 0.34 = - 0.32 V

The negative sign shows the direction of induced emf.

6 0

3 years ago

A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to

Gekata [30.6K]

Answer:

t = 1.4[s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

$P=m*v\\or\\P=F*t$

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 50 [kg]

v = velocity [m/s]

F = force = 200[N]

t = time = [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

$(m_{1}*v_{1})-F*t=(m_{1}*v_{2})$

where:

m₁ = mass of the object = 50 [kg]

v₁ = velocity of the object before the impulse = 18.2 [m/s]

v₂ = velocity of the object after the impulse = 12.6 [m/s]

$(50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s]$

3 0

3 years ago

What is the internal resistance of an automobile battery that has an emf of 12.0 V and a terminal voltage of 18.4 V while a curr

Effectus [21]

Answer:

0.888 ohm

Explanation:

We have given that the battery has an emf of 12 volt that E =12 volt

Terminal voltage V =18.4 volt

Current through the battery is =7.20 A

We have top find the internal resistance of the battery

Now according to Kirchhoff's law V=E+IR

So $R=\frac{V-E}{I}=\frac{18.4-12}{7.2}=0.888\ ohm$

So the value of internal resistance of battery is 0.888 ohm

5 0

3 years ago