Answer:

Explanation:
Let assume that ball begins its movement at a height of zero. The height can be found by energy approach, to be precise, by Principle of Energy Conservation:


Answer:
3.036×10⁻¹⁰ N
Explanation:
From newton's law of universal gravitation,
F = Gm1m2/r² .............................. Equation 1
Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.
G = gravitational constant
Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²
Substituting into equation 1
F = 6.67×10⁻¹¹×7.9×6.1/2²
F = 321.427×10⁻¹¹/4
F = 30.36×10⁻¹¹
F = 3.036×10⁻¹⁰ N
Hence the force between the balls = 3.036×10⁻¹⁰ N
Answer:
Difference in Twin's Ages = 12.68 years
Explanation:
Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.
t = t₀/[√(1 - v²/c²)]
where,
t = time measured by the person in relative motion = 1 year
t₀ = time measured by the person at rest = ?
v = speed of relative motion = 0.96 c
c = speed of light
Therefore,
1 year = t₀/[√(1 - 0.96² c²/c²)]
1 year = t₀/[√(1 - 0.9216)]
(1 year)(0.28 year) = t₀
t₀ = 0.28 year
Let,
y = Sue's age
x = Lou's age
so,
x - y = 13.4 years
but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,
x = x + 1
y = y + 0.28
Therefore,
(x + 1 year) - (y + 0.28 year) = 13.4 years
x - y = 13.4 years - 0.72 year
x - y = 12.68 years
<u>Difference in Twin's Ages = 12.68 years</u>
Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North