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mel-nik [20]
3 years ago
8

A particular circular track on level ground has a circumference of 400 m. a walker, traveling counterclockwise and starting at t

he southernmost point of the track, completes one lap in 800 s, ending his circular trip by arriving again at the southernmost point. find the average speed and the average velocity for the walker's trip around the track.
Physics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

Average speed: 0.5 m/s. Average velocity: 0

Explanation:

Average speed is given by:

v=\frac{d}{t}

where

d is the total distance covered (the length, of one lap of the track, so d = 400 m)

t is the time taken to cover that distance (so, t = 800 s)

Substituting,

v=\frac{400}{800}=0.5 m/s

Instead, average velocity is defined as

v=\frac{d}{t}

where this time,

d is the displacement, which is the vector connecting the starting point to the final point of the motion

t is still the time taken (800 s)

However, in this case the walker starts and finishes his trip at the same point: therefore, the displacement is zero (d=0), and this means that the average velocity is zero as well.

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Projectile A is launched horizontally at a speed of 20. Meters per second from the top of a cliff and strikes a level surface be
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consider the motion of projectile A in vertical direction :

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a = acceleration of the projectile = g = acceleration due to gravity = 9.8 m/s²

t = time of travel for projectile A = 3.0 seconds

Y = vertical displacement of projectile A = height of the cliff = h = ?

using the kinematics equation along the vertical direction as

Y = v₀ t + (0.5) a t²

h = (0) (3.0) + (0.5) (9.8) (3.0)²

h = 44.1 m

4 0
3 years ago
) Water falls from a height of 60m at the rate of 15kg/s to operate a turbine. The losses due to frictional force are 10% of ene
Angelina_Jolie [31]

Answer:

8100W

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3 0
3 years ago
A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displa
Lesechka [4]
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:
U_i= \frac{1}{2} ka^2
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And the total energy of the system is
E_i = U_i+K= \frac{1}{2}ka^2

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:
U_f = 0
while the mass is moving at speed v, and therefore the kinetic energy is
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And the total energy is
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For the law of conservation of energy, the total energy must be conserved, therefore E_i = E_f. So we  can write
\frac{1}{2} ka^2 =  \frac{1}{2}mv^2
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6 0
3 years ago
PLEASE HELP ME SOMEONE
sasho [114]
I think its B or D, most likely D.
7 0
3 years ago
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