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mel-nik [20]
3 years ago
8

A particular circular track on level ground has a circumference of 400 m. a walker, traveling counterclockwise and starting at t

he southernmost point of the track, completes one lap in 800 s, ending his circular trip by arriving again at the southernmost point. find the average speed and the average velocity for the walker's trip around the track.
Physics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

Average speed: 0.5 m/s. Average velocity: 0

Explanation:

Average speed is given by:

v=\frac{d}{t}

where

d is the total distance covered (the length, of one lap of the track, so d = 400 m)

t is the time taken to cover that distance (so, t = 800 s)

Substituting,

v=\frac{400}{800}=0.5 m/s

Instead, average velocity is defined as

v=\frac{d}{t}

where this time,

d is the displacement, which is the vector connecting the starting point to the final point of the motion

t is still the time taken (800 s)

However, in this case the walker starts and finishes his trip at the same point: therefore, the displacement is zero (d=0), and this means that the average velocity is zero as well.

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Alchen [17]

Answer:

h = 5.505\,m

Explanation:

Let assume that ball begins its movement at a height of zero. The height can be found by energy approach, to be precise, by Principle of Energy Conservation:

\frac{1}{2}\cdot (0.145\,kg)\cdot (12\,\frac{m}{s} )^{2}= \frac{1}{2}\cdot (0.145\,kg)\cdot (6\,\frac{m}{s} )^{2}+(0.145\,kg)\cdot (9,81\,\frac{m}{s^{2}} )\cdot h

h = 5.505\,m

4 0
3 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
4 years ago
As part of previous adventures, formerly conjoined identical twin, Sue, is now 13.4 years younger than her identical twin Lou. (
8_murik_8 [283]

Answer:

Difference in Twin's Ages = 12.68 years

Explanation:

Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.

t = t₀/[√(1 - v²/c²)]

where,

t = time measured by the person in relative motion = 1 year

t₀ = time measured by the person at rest = ?

v = speed of relative motion = 0.96 c

c = speed of light  

Therefore,

1 year = t₀/[√(1 - 0.96² c²/c²)]

1 year = t₀/[√(1 - 0.9216)]

(1 year)(0.28 year) = t₀

t₀ = 0.28 year

Let,

y = Sue's age

x = Lou's age

so,

x - y = 13.4 years

but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,

x = x + 1

y = y + 0.28

Therefore,

(x + 1 year) - (y + 0.28 year) = 13.4 years

x - y = 13.4 years - 0.72 year

x - y = 12.68 years

<u>Difference in Twin's Ages = 12.68 years</u>

6 0
4 years ago
A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

∆P = 1500(25-15)

∆P = 1500×10

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x = 25m/s

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y = -15m/s

Direction of the car change

θ = tan^-1(y/x)

θ = tan^-1(-15/25)

θ = tan^-1(-0.6)

θ = -30.96°

Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

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