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Yakvenalex [24]
3 years ago
15

IikiiiijjjjjHunnish uh uh Veg f to tcHelp me I have inserted a picture of the question

Physics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

I think this is correct

Explanation:

frequency definition is the number of complete waves produced per second so if you have 100Hz, it is 100 complete waves produced in 1 seconds, and when it says vibrates 300 times in 3 seconds, you find for 1 second

vibrations is most probably the frequency in one second

1 second -----100 vibrations

thus the frequency = 100 Hz

hope this helps!!!!!!

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I need help with this answer
7nadin3 [17]

Answer:

double replacement

Explanation:

sorry if im wrong

8 0
3 years ago
Calculate the number of moles of water molecules in 12 dm' of water<br>vapour at STP.<br><br>​
Vinvika [58]

Answer:

22.4 \:  {dm}^{3}  \: are \: occupied \: by \: 1 \: mole \\ 12 \:  {dm}^{3}  \: will \: be \: occupied \: by \: (  \frac{12}{22.4} ) \: moles \\  = 0.536 \: moles

4 0
2 years ago
Someone help this is a test and i need to finish this quick i will give brainliest of it lets me
tekilochka [14]

Sorry, I don't know but I think the correct answer is the first option.

7 0
2 years ago
What is the gravitational potential energy of a 65.7 kg person standing on the roof of a 135 meter building?
horrorfan [7]
For the purpose we will use the following equation for potential energy:
U = m * g * h
In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth).
When we plug values into the equation, we get following:
U= 65.7kg * 9.8 N/kg *135m = 86921.1 J = 86.92 kJ

8 0
3 years ago
A cat is shot horizontally out of a cannon that is on top of a 125 meter tall cliff. If the cat lands 286 m away from the base o
Elden [556K]

The initial velocity of the cat is 56.6 m/s

Explanation:

The motion of the cat is a projectile motion, consisting of:

- a uniform horizontal motion with constant velocity

- a vertical accelerated motion with constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:

s=ut+\frac{1}{2}at^2

where we have (choosing downard as positive direction)

s = 125 m is the vertical displacement of the cat

u = 0 is the initial vertical velocity

t is the time taken to reach the ground

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(125)}{9.8}}=5.05 s

Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by

v_x =\frac{d}{t}

where

d = 286 m is the horizontal distance travelled

t = 5.05 s is the time taken

Solving the equation,

v_x = \frac{286}{5.05}=56.6 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
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