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2 years ago

Explain the effects distance and mass have on the gravitational pull of the planets.

Chemistry

1 answer:

Slav-nsk [51]2 years ago

4 0

Answer:

Gravity is normal...

Explanation:

Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass. So, theoretically speaking planets move or get pulled due to their huge amount of mass.

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What exactly is a proton? Is it a member of the periodic table?

Pavel [41]

The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).

4 0

2 years ago

These little bunnies (A, B, and C) were born in the same litter to the same parents, but they have different traits for the feat

marta [7]

Answer:

Due to random assortment and incomplete dominance of alleles.

Explanation:

The bunnies end up with ear thicknesses that are different from one another due to random assortment of alleles during gamete formation according to Mendel.

In addition to random assortment, the allele for thick ear also displayed what is known as incomplete dominance over the allele for thin ear to arrive at an average ear thickness.

3 0

3 years ago

This graph shows the solution to the inequality y > 3x + 14 and y < 3x + 2

erik [133]

For apex the answer is no solution

7 0

2 years ago

An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the

san4es73 [151]

Answer:

the ionic radius of the anion $r^- = 312.52 \ pm$

Explanation:

From the diagram shown below :

The anion $Cl^-$ is located at the corners

The cation $Cs^+$ is located at the body center

The Body diagonal length = $\sqrt{3 \ a }$

∴ $2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a} \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a$

Given that :

$\frac{r^+}{r^-} =0.84$ (i.e the ratio of the ionic radius of the cation to the ionic radius of

the anion )

$0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a \\ \\ 1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a$

Also ; a = 664 pm

Then :

$r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm$

Therefore, the ionic radius of the anion $r^- = 312.52 \ pm$

4 0

3 years ago

Question 11 (10 points)

andrey2020 [161]

Answer:

The correct answer is option a.

Explanation:

When aluminum hydroxide reacts with of nitrous acid it gives of aluminum nitrite and of water.

$Al(OH)_3+3HNO_2\rightarrow Al(NO_2)_3+3H_2O$

According to above reaction ,when 1 mole of aluminum hydroxide reacts with 3 moles of nitrous acid it gives 1 mole of aluminum nitrite and 3 moles of water.

Hence, the correct answer is option a.

4 0

3 years ago