Answer:
Proof is given below
Explanation:
The length contraction is given by Δx = Δx' *√(1 - v² / c²)
where Δx' is the proper length and is measured in the frame where the object is at rest
Since the y' and z' axes are perpendicular to the direction of motion there is no contraction
So if you let V0 = Δy' * Δz' *Δx'
and V = Δy * Δz * Δx = Δy'* Δz' * Δx
Then
V = V0 * √(1 - v² / c²)
Answer:
Maximum horizontal distance covered by both the stones will be same because the speed at which both the stones are thrown is same.
However, stone that is thrown upward will spend more time in the air as compared to the stone that is thrown downward because of the projectile and vertical component of the velocity.
Answer:
Yes i am agree with this suggestion
Explanation:
Given that we have to assume that there is no any frictional affects.
As we know that when height increases then the discharge level will decreases when discharge level decreases then the time of filling for the bucket will increase.So the bucket will fill faster if the hose lowered until knee level.
Yes i am agree with this suggestion
Explanation:
A substance with a short , medium, free path has improved electron flow resistance and a higher electrical resistance . Heat applications impose more molecular chaos on all materials and shorten the track further, increasing resistance of most materials. So, just refresh the material to expand the course. In certain materials, when cooled to the minimum temperature, the conductivity is substantially increased.
Answer:
Time take to fill the standing wave to the entire length of the string is 1.3 sec.
Explanation:
Given :
The length of the one end 
, frequency of the wave 
= 2.3 Hz, wavelength of the wave λ = 1 m.
Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.
We know,
∴ 
λ
Where 
speed of the standing wave.
also, ∴ 
where 
time take to fill entire length of the string.
Compare above both equation,
⇒ 
sec
Therefore, the time taken to fill entire length 0f the string is 1.3 sec.
